从n个元素中有重复地取r个,不计其顺序,则不同的取法有C(r,n+r-1)种。
lucas模版
#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #define MOD 10007 #define LL long long using namespace std; LL qmod(LL a, LL b, LL c) { LL ans = 1; a = a % c; while(b) { if(b&1) ans = (ans*a)%c; b = b>>1; a = (a*a)%c; } return ans; } LL c(LL m,LL n) { if(m < n) return 0; if(m == n) return 1; if(n > m-n) n = m-n; LL mm = 1,nn = 1; for(LL i = 0;i < n;i++) { mm = mm*(m-i)%MOD; nn = nn*(n-i)%MOD; } return mm*qmod(nn,MOD-2,MOD)%MOD; } LL lucas(LL m,LL n) { LL ans = 1; while(m && n && ans) { ans = ans%MOD*c(m%MOD,n%MOD)%MOD; n /= MOD; m /= MOD; } return ans; } int main() { LL n,m; while(~scanf("%lld%lld",&m,&n)) printf("%lld\n",lucas(m+n-1,n)); return 0; } //XDOJ1057
时间: 2024-10-12 15:50:19