Problem A: Guess
Time Limit: 1 Sec Memory Limit: 32 MB
Description
In the television program "Shopping Street" of CCTV-2, two people, A and B are guessing the price of a given item. You are asked to decide whose price is closer to the real price.
Input
There are multiple test cases. The first line of input is an integer T (T <= 20) indicating the number of test cases.
Each case contains three integers in one line: P, PA, PB (0 <= PA, PB, P <= 100, | PA – P | != | PB – P |), indicating the real price, the price A guesses and the price B guesses.
Output
For each case, output "A" or "B" according to whose price is closer to the real price.
Sample Input
4 10 8 7 20 20 19 100 9 50 50 39 60
Sample Output
A A B B
HINT
简单题 直接上代码:
#include<stdio.h> #include<string.h> int main() { int t,a,b,c; scanf("%d",&t); while(t--) { scanf("%d%d%d",&a,&b,&c); b = (b-a)>0?(b-a):(a-b); c = (c-a)>0?(c-a):(a-c); if(b>c) printf("B\n"); else printf("A\n"); } return 0; } /************************************************************** Problem: 1 User: Hui Language: C Result: 正确 Time:0 ms Memory:964 kb ****************************************************************/
Guess
时间: 2024-10-24 19:20:09