cakephp , the subquery (2)

Cakephp 框架帮我们做了很多的工作，的确省了我们很多工作，提高了效率。

但是，碰到一些比较复杂的查询时，还是有些问题，官方的cookbook api 有说明一些详细的用法，但感觉还是不太够，有些地方讲的不够清楚。

StackOverflow上的这个问题不错

http://stackoverflow.com/questions/5770032/cakephp-and-subquery

The Question:

How can I write SQL subquery using cake syntax. I know how to code simple query, but I can‘t handle subquery.

This is the original query:

SELECT Assumption.id, Referee.id, Referee.first_name, Referee.second_name
FROM referees AS Referee
INNER JOIN (

    SELECT a.id, a.referee_id
    FROM assumptions a
    WHERE a.season_id =7
) AS Assumption ON Referee.id = Assumption.referee_id

The answer

Since you didn‘t understand the syntax, this is the actual query:

$records = $this->Referee->find(‘all‘, array(
                ‘fields‘ => array(
                    ‘Assumption.id‘, ‘Referee.id‘, ‘Referee.first_name‘, ‘Referee.second_name‘
                    ),
                ‘joins‘ => array(
                    array(
                        ‘table‘ => ‘assumptions‘,
                        ‘alias‘ => ‘Assumption‘,
                        ‘type‘  => ‘INNER‘,
                        ‘foreignKey‘    => false,
                        ‘conditions‘    => array(‘Referee.id = Assumption.referee_id‘, ‘Assumption.season_id = 7‘),
                        ),
                ),
            )
        );

　　Which produces this query:

SELECT
    `Assumption`.`id`,
    `Referee`.`id`,
    `Referee`.`first_name`,
    `Referee`.`second_name`
FROM `referees` AS `Referee`
INNER JOIN assumptions AS `Assumption`
    ON (`Referee`.`id` = `Assumption`.`referee_id`
        AND `Assumption`.`season_id` = 7)

Which provide the results you are looking for.

Sample output:

Array
(
    [0] => Array
        (
            [Assumption] => Array
                (
                    [id] => 1
                    [0] => Array
                        (
                            [id] => 1
                            [season_id] => 7
                            [referee_id] => 1
                            [name] => SomeAssumpton
                        )

                )

            [Referee] => Array
                (
                    [id] => 1
                    [first_name] => Ref
                    [second_name] => one
                )

        )

)

　　Another Answer

so after what seemed like years (several hours) and reading cake source... if you want to simply type your subquery into your cake conditions...

it uses php stdClass not an array entry... it will just dump your "value" into the query...

 $subquery = new stdClass();
    $subquery->type = "expression";
    $subquery->value = "Product.id IN (select product_id from product_categories where category_id=‘$category_id‘ or belongs_to=‘$category_id‘)";

    $options[‘conditions‘][] = $subquery;  <- dump the class into your conditions array!

do normal query $this->table->find(‘all‘, $options)

EXAMPLE: (normal cake with subquery quickfix)

//only from my vendor
    $options[‘conditions‘][‘collection_id‘] = $vendor_id;

    //inner join to CollectionProduct
    $options[‘joins‘][0] = array(
        "table" => "collection_products",
        "alias" => "CollectionProduct",
        "type"  => "INNER",
        "conditions" => array(
            "Product.id = CollectionProduct.product_id",
        ),
    );

    //show only from current category
    if ($category_id) {
        $subquery = new stdClass();
        $subquery->type = "expression";
        $subquery->value = "Product.id IN (select product_id from product_categories where category_id=‘$category_id‘ or belongs_to=‘$category_id‘)";
        $options[‘conditions‘][] = $subquery;
    } else {
        //get 18 random items... no category selected?
        $options[‘limit‘] = 18;
    }

    return $this->find(‘all‘, $options);