题目传送门
sol:Pollard_Rho的模板题,刚看了Pollard_Rho和Miller_Rabin很多原理性的东西看不懂,只是记住了结论勉强能敲代码。
- Pollard_Rho
#include "cstdio" #include "cstdlib" #include "algorithm" #include "ctime" using namespace std; typedef long long LL; LL gcd(LL a, LL b) { return b == 0 ? a : gcd(b, a % b); } LL muli_mod(LL n, LL k, LL p) { LL m = 0; while (k) { if (k & 1) m = (m + n) % p; n = (n + n) % p; k >>= 1; } return m; } LL pow_mod(LL n, LL k, LL p) { LL m = 1; while (k) { if (k & 1) m = muli_mod(m, n, p); n = muli_mod(n, n, p); k >>= 1; } return m; } LL miller_rabin(LL n) { if (n == 2) return true; if (n < 2 || !(n & 1)) return false; LL m = n - 1; int s = 0; while (!(m & 1)) s++, m >>= 1; for (int i = 1; i <= 5; i++) { LL r = rand() % (n - 1) + 1; LL y = pow_mod(r, m, n); for (int j = 1; j <= s; j++) { LL x = muli_mod(y, y, n); if (x == 1 && y != 1 && y != n - 1) return false; y = x; } if (y != 1) return false; } return true; } LL pollard_rho(LL n, LL c) { int i = 1, k = 2; LL x = rand() % (n - 1) + 1; LL y = x; while (true) { x = (muli_mod(x, x, n) + c) % n; LL p = gcd((y - x + n) % n, n); if (p > 1 && p < n) return p; if (x == y) return n; if (++i == k) { k <<= 1; y = x; } } } LL find(LL n) { if (miller_rabin(n)) return n; LL p = n; while (p >= n) p = pollard_rho(p, rand() % (n - 1) + 1); return min(find(p), find(n / p)); } int main() { int t; LL n; // srand(time(NULL)); scanf("%d", &t); while (t--) { scanf("%lld", &n); LL p = find(n); if (p == n) puts("Prime"); else printf("%lld\n", p); } return 0; }
POJ不让用万能头,algorithm下的__gcd也不让用。关键srand用一下还RE,挺坑的。
原文地址:https://www.cnblogs.com/Angel-Demon/p/11593930.html
时间: 2024-10-16 17:23:57