(Easy) Diet Plan Performance LeetCode Contest

Description:

5174. Diet Plan Performance

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• Difficulty:Easy

A dieter consumes calories[i] calories on the i-th day.  For every consecutive sequence of k days, they look at T, the total calories consumed during that sequence of k days:

• If T < lower, they performed poorly on their diet and lose 1 point;
• If T > upper, they performed well on their diet and gain 1 point;
• Otherwise, they performed normally and there is no change in points.

Return the total number of points the dieter has after all calories.length days.

Note that: The total points could be negative.

Example 1:

Input: calories = [1,2,3,4,5], k = 1, lower = 3, upper = 3
Output: 0
Explaination: calories[0], calories[1] < lower and calories[3], calories[4] > upper, total points = 0.

Example 2:

Input: calories = [3,2], k = 2, lower = 0, upper = 1
Output: 1
Explaination: calories[0] + calories[1] > upper, total points = 1.

Example 3:

Input: calories = [6,5,0,0], k = 2, lower = 1, upper = 5
Output: 0
Explaination: calories[0] + calories[1] > upper, calories[2] + calories[3] < lower, total points = 0.

Constraints:

• 1 <= k <= calories.length <= 10^5
• 0 <= calories[i] <= 20000
• 0 <= lower <= upper

Solution:

class Solution {
    public int dietPlanPerformance(int[] calories, int k, int lower, int upper) {

        if(calories==null||calories.length ==0){
            return 0;
        }
        int points=0;

        int i = 0;
        int times = calories.length /k;

        for( i = 0; i+k<=calories.length; i++){

                int [] a = new int[k];
                int count =0;
                int tmp_sum = 0;
                for(int j = i; count< k; j++ ){
                    tmp_sum = tmp_sum + calories[j];
                    count++;

                }

                if(tmp_sum<lower){
                    points = points -1;
                }

                if(tmp_sum>upper){

                    points = points+1;
                }

            }
         return points;

        }

        public int sum (int[] a ){
        int sum = 0;
        for(int i = 0; i<a.length; i++){
            sum = sum+a[i];
        }

        return sum;
    }

    }

原文地址：https://www.cnblogs.com/codingyangmao/p/11441778.html