python 字典所有操作

# 字典的创建# dict1 = {}# print(type(dict1))## dict2 = {#         ‘name‘:‘汪峰‘,#         ‘sex‘:‘男‘,#         ‘hiredate‘:‘1997-10-20‘#         }# print(dict2)## dict3 = dict(name = ‘eric‘,age = 28)# print(dict3)

#  取值操作# employee = {#         ‘name‘:‘汪峰‘,#         ‘sex‘:‘男‘,#         ‘grade‘:‘A‘,#         ‘hiredate‘:‘1997-10-20‘,#         ‘salary‘: 1000,#         ‘welfare‘:100#         }# name = employee[‘name‘]# print(name)## sex = employee.get(‘sex‘)# print(sex)## dept = employee.get(‘dept‘,‘其他部门‘)# print(dept)

# in 成员运算符  判断 key 是否存在# print(‘name‘ in employee)  # True# print(‘dept‘ in employee)  # False# print(‘dept‘ not in employee)  # True

# 遍历字典# 汪峰# 男# 1997-10-20# for key in employee:#     v = employee[key]#     print(v)

# name 汪峰# sex 男# hiredate 1997-10-20# for k,v in employee.items():#     print(k,v)

# 单个更新# employee[‘grade‘] = ‘B‘# print(employee)# # 多个更新# employee.update(salary = 1200, welfare = 150)# print(employee)## # 新增# employee[‘dept‘] = ‘研发部‘# print(employee)## #  删除操作# employee.pop(‘dept‘)# print(employee)# #  删除操作  删除最后一个 kv# employee.popitem()# print(employee)## # 清空字典# employee.clear()# print(employee)

# emp1 = {‘name‘:‘jacky‘,‘grade‘:‘B‘,‘hiredate‘:‘1989-10-12‘}# emp2 = {‘name‘:‘Lily‘,‘grade‘:‘A‘,‘hiredate‘:‘1989-10-12‘}## # setdefault 设置默认值 存在就忽略 不存在就创建# emp2.setdefault(‘grade‘,‘C‘)# print(emp2)

#  获取字典的视图# k = emp1.keys()# # dict_keys([‘name‘, ‘grade‘])# print(k)## v = emp1.values()# # dict_values([‘jacky‘, ‘B‘])# print(v)## items = emp1.items()# # dict_items([(‘name‘, ‘jacky‘), (‘grade‘, ‘B‘)])# print(items)

# 格式化字符串# emp_str = "姓名:{name},评级:{grade},入职时间{hiredate}".format_map(emp1)# print(emp_str)

# 散列值# h1 = hash("dabc")# # print(h1)# # h2 = hash("1231231")# # print(h2)

# 例子source = "12345,jace,ercd,php,5000$2345,clead,ercd,dfd,5000$22345,clead,ercd,dfd,5000$32345,clead,ercd,dfd,5000"employee_list = source.split("$")print(employee_list)

all_emp = {}for i in range(0,len(employee_list)):    # print(i)    e = employee_list[i].split(",")    # print(e)    employee = {‘no‘:e[0],‘name‘:e[1],‘www‘:e[2],‘jod‘:e[3],‘salary‘:e[4]}    print(employee)    all_emp[employee[‘no‘]] = employeeprint(all_emp)

empno = input(‘编号:‘)if empno in all_emp:    emp = all_emp.get(empno)    print(emp);else:    print(‘编号不存在‘)

原文地址：https://www.cnblogs.com/ericblog1992/p/11271922.html