LeetCode 027 Remove Element

题目要求:Remove Element

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.

代码如下:

class Solution {
public:
    int removeElement(int A[], int n, int elem) {

        if(n == 0) return 0;

        int index = 0;
        for(int i = 0; i < n; i++){
            if(A[i] != elem)
                A[index++] = A[i];
        }

        return index;
    }
};
时间: 2024-10-24 07:47:11

LeetCode 027 Remove Element的相关文章

[LeetCode] 027. Remove Element (Easy) (C++)

索引:[LeetCode] Leetcode 题解索引 (C++/Java/Python/Sql) Github: https://github.com/illuz/leetcode 027. Remove Element (Easy) 链接: 题目:https://oj.leetcode.com/problems/remove-element/ 代码(github):https://github.com/illuz/leetcode 题意: 删除一个数组里值为 elem 的所有数. 分析: 用

Java for LeetCode 027 Remove Element

Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 解题思路: 看代码即可 JAVA实现如下: public int removeElement(int[] nums

LeetCode:Remove Element

Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. Solution: class Solution { public: int removeElement(int

leetCode 27.Remove Element (删除元素) 解题思路和方法

Remove Element Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 思路:此题和26题一脉相承,算法上不难,具体如代码所示: public class

LeetCode 27.Remove Element 数组元素删除

27. Remove Element Given an array and a value, remove all instances of that value in place and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. The order of elements can be changed.

【LeetCode】Remove Element

Remove Element Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 解法一:使用vector记录每个elem的位置,介于这些位置之间的元素就可以前移相应

【LeetCode】027. Remove Element

题目: Given an array and a value, remove all instances of that value in place and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. The order of elements can be changed. It doesn't mat

leetcode 27 Remove Element

Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 题解:水题.遇到val就和最后一个不是val的数交换位置就好了. class Solution { public:

[leetcode 50]remove element

1 题目 Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. Hide Tags Array Two Pointers 2 思路 好吧,感觉这个题目出的不是很好,按照