https://leetcode.com/submissions/detail/32662938/
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______6______ / ___2__ ___8__ / \ / 0 _4 7 9 / 3 5
For example, the lowest common ancestor (LCA) of nodes 2
and 8
is 6
. Another example is LCA of nodes 2
and 4
is 2
, since a node can be a descendant of itself according to the LCA definition.
Leetcode又出新题啦
SOLUTION 1:
使用递归可以轻松解决此问题。对于此题我们可以分为三种情况讨论:
1. P, Q都比root小,则LCA在左树,我们继续在左树中寻找LCA
2. P, Q都比root大,则LCA在右树,我们继续在右树中寻找LCA
3. 其它情况,表示P,Q在root两边,或者二者其一是root,或者都是root,这些情况表示root就是LCA,直接返回root即可。
代码如下:
1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) { 12 // 1439. 13 // 1. Two nodes are on left, go left. 14 // 2. Two nodes are on right, go right. 15 // 3. They are in both sides, return root. 16 // if root == null, return null. 17 if (root == null) { 18 return null; 19 } 20 21 if (p.val < root.val && q.val < root.val) { 22 return lowestCommonAncestor(root.left, p, q); 23 } else if (p.val > root.val && q.val > root.val) { 24 return lowestCommonAncestor(root.right, p, q); 25 } else { 26 return root; 27 } 28 } 29 }