SQL题目备忘

1. 列出每个部门年龄最大的员工姓名，部门名等信息
2. 列出每个部门的员工总收入
3. 列出员工总收入大于8000的部门号，部门名称信息
4. 有哪个部门还有员工未入职
5. 按部门号大小，入职时间由早到晚排序员工信息表

1.sqlite> SELECT e.e_name, MAX(e.e_age), d.name FROM employee e

...> INNER JOIN dept d ON e.e_dept_id=d.id
       ...> GROUP BY e.e_dept_id;

2.sqlite> SELECT SUM(e.e_salary), d.name FROM employee e

...> INNER JOIN dept d ON e.e_dept_id=d.id
       ...> GROUP BY e.e_dept_id;

3.sqlite> SELECT e.e_dept_id, d.name FROM employee e

...> INNER JOIN dept d ON e.e_dept_id=d.id
       ...> GROUP BY e.e_dept_id
       ...> HAVING SUM(e.e_salary)>8000;

4.sqlite> SELECT d.id, d.name FROM dept d

       ...> WHERE d.id NOT IN
       ...> (SELECT e.e_dept_id FROM employee e);

5.sqlite> SELECT * FROM employee e
        ...> ORDER BY e.e_dept_id ASC, e_time ASC;

1. 查询每个部门及部门平均工资并按薪资由高到低排序
2. 查询部门及其最高薪资员工ID

1.sqlite> SELECT d.dept, AVG(s.salary) FROM dept d

       ...> INNER JOIN employee e ON d.name=e.name
       ...> INNER JOIN salary s ON e.id=s.id
       ...> GROUP BY d.dept
       ...> ORDER BY AVG(s.salary) DESC;

2.sqlite> SELECT d.dept, s.id, e.name, MAX(s.salary) FROM dept d

       ...> INNER JOIN employee e ON d.name=e.name
       ...> INNER JOIN salary s ON e.id=s.id
       ...> GROUP BY d.dept;