https://pintia.cn/problem-sets/994805260223102976/problems/994805272659214336
本题的基本要求非常简单:给定N个实数,计算它们的平均值。但复杂的是有些输入数据可能是非法的。一个“合法”的输入是[-1000,1000]区间内的实数,并且最多精确到小数点后2位。当你计算平均值的时候,不能把那些非法的数据算在内。
输入格式:
输入第一行给出正整数N(<=100)。随后一行给出N个实数,数字间以一个空格分隔。
输出格式:
对每个非法输入,在一行中输出“ERROR: X is not a legal number”,其中X是输入。最后在一行中输出结果:“The average of K numbers is Y”,其中K是合法输入的个数,Y是它们的平均值,精确到小数点后2位。如果平均值无法计算,则用“Undefined”替换Y。如果K为1,则输出“The average of 1 number is Y”。
输入样例1:
7
5 -3.2 aaa 9999 2.3.4 7.123 2.35
输出样例1:
ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38
输入样例2:
2
aaa -9999
输出样例2:
ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined
代码:
#include <bits/stdc++.h> using namespace std; const int maxn = 1e5 + 10; char s[maxn]; double num[1111]; int main() { int T; scanf("%d", &T); double sum = 0; int dot = 0; for(int j = 1; j <= T;j ++) { scanf("%s", s); int len = strlen(s); bool flag = true; int cnt = 0, temp, ans = 0; for(int i = 0; i < len; i ++) { if(!((s[i] >= ‘0‘ && s[i] <= ‘9‘) || s[i] == ‘-‘ || s[i] == ‘.‘ || s[i] == ‘+‘)) flag=false; /* if(s[0]==‘.‘||s[len-1]==‘.‘) flag=false; */ if(s[i]==‘-‘&&i>0) flag=false; if(s[0]==‘-‘&&len==1) flag=false; if(s[i]==‘+‘&&i>0) flag=false; if(s[0]==‘+‘&&len==1) flag=false; if(s[i] == ‘.‘) { cnt ++; if(cnt > 1) flag = false; else if(cnt == 1) { temp = i; if(len - temp > 3) flag = false; } } } if(flag) { ans ++; num[ans] = atof(s); for(int i = 1; i <= ans; i ++) { if(num[i] >= -1000 && num[i] <= 1000) { dot ++; sum += num[i]; } else flag = false; } } if(!flag) printf("ERROR: %s is not a legal number\n", s); } if(dot == 1) printf("The average of %d number is %.2lf\n", dot, sum/dot); else if(dot>1) printf("The average of %d numbers is %.2lf\n", dot, sum/dot); else printf("The average of 0 numbers is Undefined\n"); return 0; }
原文地址:https://www.cnblogs.com/zlrrrr/p/9380123.html
时间: 2024-11-07 10:48:08