判断对象的属性值是否为null

核心处理：

    private Object getFieldValueByName(String fieldName, Object o) {
        try {
            String firstLetter = fieldName.substring(0, 1).toUpperCase();
            String getter = "get" + firstLetter + fieldName.substring(1);
            Method method = o.getClass().getMethod(getter, new Class[] {});
            Object value = method.invoke(o, new Object[] {});
            return value;
        } catch (Exception e) {
            logger.error(e.getMessage(), e);
            return null;
        }
    }

运用示例：

        DoctorVo doctorVo = new DoctorVo();
        // doctorVo.setId(3942);
        Object id = this.getFieldValueByName("id", doctorVo);
        if (null != id) {
            bdId = doctorVo.getId();
            logger.info("传递了医生ID，doctorId = " + bdId);
        }

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