在nagios中需要检测cockroach、nomad、consul服务集群节点状态的脚本，查看服务集群状态的命令是：
1.consul查看群集节点状态的命令 .[[email protected] ~]# consul members
Node Address Status Type Build Protocol DC Segment
cgw122.zencoo.com 192.168.196.122:8301 alive server 1.4.3 2 cd <all>
cws113.zencoo.com 192.168.196.113:8301 alive server 1.4.3 2 cd <all>
mandrill.zencoo.com 192.168.196.205:8301 alive client 1.4.3 2 cd <default>
主要关注build那列，看是不是都是alive，如果都是，状态就正常，cockroach、nomad也类似这样，对这些服务完全不了解。
2.脚本如下：
#!/bin/bash
#Detection cockroach status
function cockroach { #检测cockroach群集节点状态的函数
NUM=cat /tmp/.cockroach.status|awk ‘{print $9}‘|grep ‘true‘|wc -l
[ "$1" -eq "$NUM" ] && (echo "$NUM nodes is alive";exit 0) || (echo "Only $NUM nodes is alive,expect $1";exit 2)
}
#Detection nomad status
function nomad { #检测nomad群集节点状态的函数
NUM=cat /tmp/.nomad.status |grep ready|wc -l
[ "$1" -eq "$NUM" ] && (echo "$NUM nodes is alive";exit 0) || (echo "Only $NUM nodes is alive,expect $1";exit 2)
}
#Detection consul status
function consul { #检测consul群集节点状态的函数
NUM=cat /tmp/.consul.status |grep alive|wc -l
[ "$1" -eq "$NUM" ] && (echo "$NUM nodes is alive";exit 0) || (echo "Only $NUM nodes is alive,expect $1";exit 2)
}
case $1 in
cockroach)
cockroach $2;;
nomad)
nomad $2 ;;
consul)
consul $2 ;;
esac
2.1.判断每个服务有几个节点存活，将存活的节点数量赋值给NUM变量
2.2.case中的$2是传入的节点数量个数，到函数中就变成$1了
2.3.判断实际传入的节点个数($1)和检测到的存活节点个数($NUM）是否相等
2.4.在nagios中显示如下，状态正常，2 node is alive，传入的$2是2
原文地址：https://blog.51cto.com/pkimin3/2397405