python模块之HTMLParser解析出URL链接

# -*- coding: utf-8 -*-
#python 27
#xiaodeng
#python模块之HTMLParser解析出URL链接
#http://www.cnblogs.com/mfryf/p/3691563.html

from HTMLParser import HTMLParser
class MyHTMLParser(HTMLParser):
    def __init__(self):
        HTMLParser.__init__(self) #继承
        self.links = []#links 链接

    def handle_starttag(self, tag, attrs):
        #print "Encountered the beginning of a %s tag" % tag

        if tag == "a":
            if len(attrs) == 0:
                pass
            else:
                for variable, value in attrs:
                    if variable == "href":
                        self.links.append(value)   

if __name__ == "__main__":
    #写入一个html长字符串
    html_code = """<a href="www.google.com"> google.com</a>
<A Href="www.pythonclub.org"> PythonClub </a>
<A HREF = "www.sina.com.cn"> Sina </a>
"""
    hp = MyHTMLParser()
    hp.feed(html_code)
    hp.close()
    #print hp.handle_starttag(‘a‘, ‘href‘)
    print hp.links #[‘www.google.com‘, ‘www.pythonclub.org‘, ‘www.sina.com.cn‘]