HDU 2106 decimal system (进制转化求和)

题意：给你n个r进制数，让你求和。

析：思路就是先转化成十进制，再加和。

代码如下：

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <queue>
#include <vector>
#include <cstring>
#include <map>

using namespace std;
const int maxn = 70;
char s[maxn];

int main(){
    int n;
    while(~scanf("%d", &n)){
        int sum = 0;
        while(n--){
            int ss = 0;
            scanf("%s", s);
            int tt;
            for(tt = 0; s[tt] != ‘(‘; ++tt) ;

            int t = 0;
            for(int i = tt+1; s[i] != ‘)‘; ++i)
                t = t * 10 + s[i] - ‘0‘;

            for(int i = 0; s[i] != ‘(‘; ++i)
                ss = ss * t + s[i] - ‘0‘;
            sum += ss;
        }

        printf("%d\n", sum);
    }
    return 0;
}