python正则表达式抽取mysql慢查询sql本身，de-parameterize，将参数值改为?

这个问题我提在了 StackOverflow 上，但没有回答。自己写吧

我的需求是，将mysql slow queries展现到页面上。但是如果原始展现，会带不同参数，不太好group等。其实我们关心的只是sql本身，比如

-- 这俩其实是一条慢查询
select * from a where a>1 and b=‘r‘ and c=3;
select * from a where a>2 and b=‘x‘ and c=5;
-- 希望能处理到
select * from a where a>? and b=‘?‘ and c=?

因为没有很合适的module，所以得用regrex替换。数字很容易，字符串需要考虑

1. 最基本的，替换数字可以用r"\b\d+\b" 独立的一个或多个连续数字，这样不会替换如col1等对象中的数字
2. 简单地，字符串可以用r"‘[^‘]*‘" 表示2个‘之间所有非‘的连续字符，这样可以适用大多数情况，除了字符串有空格的，比如‘a   bdf c‘就不行了
3. 最严谨的方式，按‘对sql划分数组。这样所有‘‘里面的字符串都是偶数成员，其他部分奇数成员。替换偶数成员为?就可以了

代码如下import re

sql = r"select * from a where id=‘aaaaa haha wocao‘ and id1= ‘fff‘ and xx=1 and a3= 4 and a4=3434343 and a5a>99"
sql.split("‘")
#[‘select * from a where id=‘, ‘aaaaa haha wocao‘, ‘ and id1= ‘, ‘fff‘, ‘ and xx=1 and a3= 4 and a4=3434343 and a5a>99‘]
sarr = sql.split("‘")
sarr
#[‘select * from a where id=‘, ‘aaaaa haha wocao‘, ‘ and id1= ‘, ‘fff‘, ‘ and xx=1 and a3= 4 and a4=3434343 and a5a>99‘]
sarr[::2]
#[‘select * from a where id=‘, ‘ and id1= ‘, ‘ and xx=1 and a3= 4 and a4=3434343 and a5a>99‘]
sarr[1::2]
#[‘aaaaa haha wocao‘, ‘fff‘]

sarr[1::2]= [‘?‘ for x in sarr[1::2]]
sarr
#[‘select * from a where id=‘, ‘?‘, ‘ and id1= ‘, ‘?‘, ‘ and xx=1 and a3= 4 and a4=3434343 and a5a>99‘]
"‘".join(sarr)
#"select * from a where id=‘?‘ and id1= ‘?‘ and xx=1 and a3= 4 and a4=3434343 and a5a>99"
sql
#"select * from a where id=‘aaaaa haha wocao‘ and id1= ‘fff‘ and xx=1 and a3= 4 and a4=3434343 and a5a>99"

aa = "‘".join(sarr)re.sub(r"\b\d+\b","?",aa)  #"select * from a where id=‘?‘ and id1= ‘?‘ and xx=? and a3= ? and a4=? and a5a>?"