方法一
function DX(n) { if (!/^(0|[1-9]\d*)(\.\d+)?$/.test(n)) return "数据非法"; var unit = "千百拾亿千百拾万千百拾元角分", str = ""; n += "00"; var p = n.indexOf(‘.‘); if (p >= 0) n = n.substring(0, p) + n.substr(p+1, 2); unit = unit.substr(unit.length - n.length); for (var i=0; i < n.length; i++) str += ‘零壹贰叁肆伍陆柒捌玖‘.charAt(n.charAt(i)) + unit.charAt(i); return str.replace(/零(千|百|拾|角)/g, "零").replace(/(零)+/g, "零").replace(/零(万|亿|元)/g, "$1").replace(/(亿)万|壹(拾)/g, "$1$2").replace(/^元零?|零分/g, "").replace(/元$/g, "元整"); }
方法2
<script type="text/javascript">
var _change = {
ary0: ["零", "一", "二", "三", "四", "五", "六", "七", "八", "九"],
ary1: ["", "十", "百", "千"],
ary2: ["", "万", "亿", "兆"],
init: function (name) {
this.name = name;
},
strrev: function () {
var ary = []
for (var i = this.name.length; i >= 0; i--) {
ary.push(this.name[i])
}
return ary.join("");
}, //倒转字符串。
pri_ary: function () {
var $this = this
var ary = this.strrev();
var zero = ""
var newary = ""
var i4 = -1
for (var i = 0; i < ary.length; i++) {
if (i % 4 == 0) { //首先判断万级单位,每隔四个字符就让万级单位数组索引号递增
i4++;
newary = this.ary2[i4] + newary; //将万级单位存入该字符的读法中去,它肯定是放在当前字符读法的末尾,所以首先将它叠加入$r中,
zero = ""; //在万级单位位置的“0”肯定是不用的读的,所以设置零的读法为空
}
//关于0的处理与判断。
if (ary[i] == ‘0‘) { //如果读出的字符是“0”,执行如下判断这个“0”是否读作“零”
switch (i % 4) {
case 0:
break;
//如果位置索引能被4整除,表示它所处位置是万级单位位置,这个位置的0的读法在前面就已经设置好了,所以这里直接跳过
case 1:
case 2:
case 3:
if (ary[i - 1] != ‘0‘) {
zero = "零"
}
; //如果不被4整除,那么都执行这段判断代码:如果它的下一位数字(针对当前字符串来说是上一个字符,因为之前执行了反转)也是0,那么跳过,否则读作“零”
break;
}
newary = zero + newary;
zero = ‘‘;
}
else { //如果不是“0”
newary = this.ary0[parseInt(ary[i])] + this.ary1[i % 4] + newary; //就将该当字符转换成数值型,并作为数组ary0的索引号,以得到与之对应的中文读法,其后再跟上它的的一级单位(空、十、百还是千)最后再加上前面已存入的读法内容。
}
}
if (newary.indexOf("零") == 0) {
newary = newary.substr(1)
}//处理前面的0
return newary;
}
}
//创建class类
function change() {
this.init.apply(this, arguments);
}
change.prototype = _change
具体转换使用
var k = new change((i+1).toString());