Problem Description
Little Q‘s clock is alarming! It‘s time to get up now! However, after reading the time on the clock, Little Q lies down and starts sleeping again. Well, he has 5 alarms, and it‘s just the first one, he can continue sleeping for a while.
Little Q‘s clock uses a standard 7-segment LCD display for all digits, plus two small segments for the ‘‘:‘‘, and shows all times in a 24-hour format. The ‘‘:‘‘ segments are on at all times.
Your job is to help Little Q read the time shown on his clock.
Input
The first line of the input contains an integer T(1≤T≤1440), denoting the number of test cases.
In each test case, there is an 7×21 ASCII image of the clock screen.
All digit segments are represented by two characters, and each colon segment is represented by one character. The character ‘‘X‘‘ indicates a segment that is on while ‘‘.‘‘ indicates anything else. See the sample input for details.
Output
For each test case, print a single line containing a string t in the format of HH:MM, where t(00:00≤t≤23:59), denoting the time shown on the clock.
Sample Input
1
.XX...XX.....XX...XX.
X..X....X......X.X..X
X..X....X.X....X.X..X
......XX.....XX...XX.
X..X.X....X....X.X..X
X..X.X.........X.X..X
.XX...XX.....XX...XX.
Sample Output
02:38
题意：把字符串翻译成时间。
题解：直接利用他们的区别判断即可。
1 #include <iostream>
2 #include<cstdio>
3 #include<algorithm>
4 #include<queue>
5 #include<map>
6 #include<vector>
7 #include<cmath>
8 #include<cstring>
9 using namespace std;
10
11 char time[7+1][21+1];
12 int check(int i)
13 {
14 int j;
15 if(time[6][i]==‘X‘)
16 {
17 if(time[4][i+1]==‘.‘)
18 return 0;
19 else if(time[2][i]==‘.‘)
20 return 2;
21 else if(time[2][i+3]==‘.‘)
22 return 6;
23 else
24 return 8;
25 }
26 else
27 {
28 if(time[2][i]==‘X‘)
29 {
30 if(time[1][i+1]==‘X‘)
31 {
32 if(time[2][i+3]==‘X‘)
33 return 9;
34 else
35 return 5;
36 }
37 else
38 return 4;
39 }
40 else
41 {
42 if(time[4][i+1]==‘.‘)
43 {
44 if(time[1][i+1]==‘X‘)
45 return 7;
46 else
47 return 1;
48 }
49 else
50 return 3;
51 }
52 }
53 }
54
55 int main()
56 {
57 int a,b,c,d;
58 int T;
59 scanf("%d",&T);
60 while(T--)
61 {
62 for(int i=1;i<=7;i++)
63 for(int j=1;j<=21;j++)
64 cin>>time[i][j];
65 a=check(1);
66 b=check(6);
67 c=check(13);
68 d=check(18);
69 printf("%d%d:%d%d\n",a,b,c,d);
70 }
71 return 0;
72 }