[LeetCode] Median of Two Sorted Arrays 两个有序数组的中位数

There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 求两个有序数组的中位数,并限制了时间复杂度O(log (m+n)),看到这个时间复杂度,自然想到用二分搜索Binary Search. 对于一个长度为n的已

There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. Have you met this question in a real interview? Example Given A=[1,2,3,4,5,6] and B=[2,3,4,5], the median is 3.5. Given A=[1,2,3] and B=[4,5],

中位数是把一个数的集合划分为两部分,每部分包含的数字个数相同,并且一个集合中的元素均大于另一个集合中的元素. 因此,我们考虑在一个任意的位置,将数组A划分成两部分.i表示划分数组A的位置,如果数组A包含m个元素,则划分位置有m+1种情况.因此,i的取值范围是0~m. 当i=0时,表示left_A为空:当i=m时,表示right_A为空. 同理,我们也可以划分B数组: 我们把left_A和left_B放到一个集合中,把right_A和right_B放到一个集合中. 如果想要获得中位数,要保证len

class Solution { public: double FindKthNumber(vector<int> numbers1, vector<int>numbers2, int len1, int len2, int start1, int start2, int k){ if (len1 > len2) return FindKthNumber(numbers2, numbers1, len2, len1, start2, start1, k); if (len1

There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 解法一:不考虑时间复杂度限制在O(log(m+n)),则将两个数组遍历一遍即可以组合成一个排好序的数组,然后取数组的中位数即可,时间复杂度O(m+n): c

二分.情况讨论 class Solution { public: int findPos(int* p,int n,int x){ int low=0,high=n-1,mid; while(low<=high){ mid=(low+high)>>1; if(p[mid]<=x)low=mid+1; else high=mid-1; } return low; } double findK(int a[], int m, int b[], int n,int k){ int mid

There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 有两个已排序的数组A和B,大小为m 和 n. 找出两数组的中位数 时间复杂度应该为 O(log (m+n)). 简单粗暴的方法就是把两个数组合并成一个数组,排序,取中位数.

原题地址:https://oj.leetcode.com/problems/median-of-two-sorted-arrays/ 题意:There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 解题思路:这道题要求两个已经排好

题目 There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 原题链接(点我) 解题思路 返回两个排序数组的中位数.这个题可以有以下几个思路: 首先可以想到的是将两个数组merge起来,然后返回其中位数. 第二个是,类似merg