假设mysql用户名root 密码123456，新建测试数据表utable 脚本如下：
#!/bin/bash
#mysqlop.sh
mysql="/app/local/mysql/bin/mysql -uroot -p123456"
#sql="show databases"
#sql="show tables from test"
sql="create table test.utable(
id int unsigned auto_increment primary key,
username varchar(50),
passwd varchar(50)
)"
#sql="desc test.utable"
#sql="insert into test.utable(username,passwd) values(‘user3‘,321)"
#sql="select * from test.utable"
#sql="delete from test.utable where id=3"
#sql="update test.utable set passwd=135 where id=2"
#sql="drop table test.utable"
$mysql -e "$sql"
#sh mysqlop.sh
新建完成后需要注释掉创建语句，继续编辑脚本
#!/bin/bash
#mysql.sh
mysql="/app/local/mysql/bin/mysql -uroot -p123456"
case $1 in
select)
sql="select * from test.utable"
;;
delete)
sql="delete from test.utable where id=$2"
;;
insert)
sql="insert into test.utable(username,passwd)values(‘$2‘,‘$3‘)"
;;
update)
sql="update test.utable set username=‘$3‘,passwd=$4 where id=‘$2‘"
;;
*)
sql="select * from test.utable"
;;
esac
$mysql -e "$sql"
:x保存退出
#chmod +x mysqlop.sh
调用示例如下：
#./mysqlop.sh insert user1 321#增
#./mysqlop.sh insert user2 312#增
#./mysqlop.sh insert user3 123#增
#./mysqlop.sh insert user4 132#增
#./mysqlop.sh insert user5 213#增
#./mysqlop.sh delete 5#删
#./mysqlop.sh update 2 user6 111#改
#./mysqlop.sh select#查
#./mysqlop.sh aaa #查