Factstone Benchmark
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 1760 Accepted Submission(s): 973
Problem Description
Amtel has announced that it will release a 128-bit computer chip by 2010, a 256-bit computer by 2020, and so on, continuing its strategy of doubling the word-size every ten years. (Amtel released a 64-bit computer in 2000, a 32-bit
computer in 1990, a 16-bit computer in 1980, an 8-bit computer in 1970, and a 4-bit computer, its first, in 1960.)
Amtel will use a new benchmark - the Factstone - to advertise the vastly improved capacity of its new chips. The Factstone rating is defined to be the largest integer n such that n! can be represented as an unsigned integer in a computer word.
Given a year 1960 ≤ y ≤ 2160, what will be the Factstone rating of Amtel‘s most recently released chip?
There are several test cases. For each test case, there is one line of input containing y. A line containing 0 follows the last test case. For each test case, output a line giving the Factstone rating.
Sample Input
1960 1981 0
Sample Output
3 8
不知道为什么,就是感觉数据很水。。我感觉我写的代码应该过不了的,结果过了
代码:
#include <stdio.h> #include <math.h> #define MAX 210 #define PI 3.14159265358979323846 #define E 2.7182818284590452354 int main() { int ans[MAX] ; int j = 1 ; for(int i = 0; i < MAX ; ++i) { for( ; ; ++j) { if(0.5*log10(2*PI*j)+j*log10(j/E)>pow(2.0,i/10+2)*log10(2.0)) { ans[i] = j-1 ; break ; } } } int year ; while(~scanf("%d",&year) && year) { printf("%d\n",ans[year-1960]); } return 0 ; }
与君共勉