ZOJ 1586-Preliminary Round

E - QS Network

Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu

Submit Status

Description

Sunny Cup 2003 - Preliminary Round

April 20th, 12:00 - 17:00

Problem E: QS Network

In the planet w-503 of galaxy cgb, there is a kind of intelligent
creature named QS. QScommunicate with each other via networks. If two QS
want to get connected, they need to buy two network adapters (one for
each QS) and a segment of network cable. Please be advised that ONE
NETWORK ADAPTER CAN ONLY BE USED IN A SINGLE CONNECTION.(ie. if a QS
want to setup four connections, it needs to buy four adapters). In the
procedure of communication, a QS broadcasts its message to all the QS it
is connected with, the group of QS who receive the message broadcast
the message to all the QS they connected with, the procedure repeats
until all the QS‘s have received the message.

A sample is shown below:

A sample QS network, and QS A want to send a message.

Step 1. QS A sends message to QS B and QS C;

Step 2. QS B sends message to QS A ; QS C sends message to QS A and QS D;

Step 3. the procedure terminates because all the QS received the message.

Each QS has its favorate brand of network adapters and always buys the
brand in all of its connections. Also the distance between QS vary.
Given the price of each QS‘s favorate brand of network adapters and the
price of cable between each pair of QS, your task is to write a program
to determine the minimum cost to setup a QS network.

Input

The 1st line of the input contains an integer t which indicates the number of data sets.

From the second line there are t data sets.

In a single data set,the 1st line contains an interger n which indicates the number of QS.

The 2nd line contains n integers, indicating the price of each QS‘s favorate network adapter.

In the 3rd line to the n+2th line contain a matrix indicating the price of cable between ecah pair of QS.

Constrains:

all the integers in the input are non-negative and not more than 1000.

Output

for each data set,output the minimum cost in a line. NO extra empty lines needed.

Sample Input

1
3
10 20 30
0 100 200
100 0 300
200 300 0

Sample Output

370

把配置器的价格直接加入图中的权值里,后面就是模板了

 1 #include <stdio.h>
 2 #include <string.h>
 3 #include <algorithm>
 4 using namespace std;
 5 const int N=1010;
 6 const int inf=1<<29;
 7 int n,m,a[N],flag[N],w[N][N],dis[N];
 8 int prim()
 9 {
10     int sum=0;
11     memset(flag,0,sizeof(flag));
12     for(int i=1;i<=n;i++)
13     {
14         dis[i]=w[1][i];
15     }
16     flag[1]=1;
17     for(int i=1;i<n;i++)
18     {
19         int to=-1,min1=inf;
20         for(int j=1;j<=n;j++)
21         {
22             if(!flag[j]&&dis[j]<min1)
23             {
24                 to=j;
25                 min1=dis[j];
26
27             }
28         }
29         if(to==-1) return -1;
30         sum+=min1;
31         flag[to]=1;
32         for(int i=1;i<=n;i++)
33         {
34             dis[i]=min(dis[i],w[to][i]);
35         }
36     }
37     return sum;
38 }
39 int main()
40 {
41     int t, tmp;
42     scanf("%d",&t);
43     while(t--)
44     {
45         scanf("%d",&n);
46         for(int i=1;i<=n;i++)
47         {
48             scanf("%d",&a[i]);
49         }
50         for(int i=1;i<=n;i++)
51         {
52             for(int j=1;j<=n;j++)
53             {
54                 scanf("%d",&tmp);
55                 w[i][j] = tmp + a[i] + a[j];
56                 w[j][i] =  tmp + a[i] + a[j];
57             }
58         }
59         printf("%d\n",prim());
60     }
61     return 0;
62 }
时间: 2024-10-12 21:27:57

ZOJ 1586-Preliminary Round的相关文章

ZOJ 1584:Sunny Cup 2003 - Preliminary Round(最小生成树&amp;amp;&amp;amp;prim)

Sunny Cup 2003 - Preliminary Round April 20th, 12:00 - 17:00 Problem E: QS Network In the planet w-503 of galaxy cgb, there is a kind of intelligent creature named QS. QScommunicate with each other via networks. If two QS want to get connected, they

ZOJ 1584:Sunny Cup 2003 - Preliminary Round(最小生成树&amp;&amp;prim)

Sunny Cup 2003 - Preliminary Round April 20th, 12:00 - 17:00 Problem E: QS Network In the planet w-503 of galaxy cgb, there is a kind of intelligent creature named QS. QScommunicate with each other via networks. If two QS want to get connected, they

zoj 1586

//zoj 1586#include<iostream>#include<cstdio>using namespace std;#define N 1005int a[N][N],low[N],n,ans;int b[N]; int min(int x,int y){ return x<y?x:y; } void prim(int u0){ int i,j,m,k; ans=0; for (i=1;i<n;i++) low[i]=a[u0][i]; low[u0]=-1

ZOJ 1586 QS Network (经典MST~Prim)

链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=586 In the planet w-503 of galaxy cgb, there is a kind of intelligent creature named QS. QScommunicate with each other via networks. If two QS want to get connected, they need to buy two n

ZOJ 1586 QS Network(最小生成树 prim)

题意  输入n  然后输入n个数  代表连接时每个站点自身的消耗   然后输入n*n的矩阵  第i行第j列的数代表第i个站点和第j个站点之间路上的花费  链接i,j两个节点的总花费为两站点自身花费加上路上的花费  求⑩这n个站点连通的最小总花费 又是裸的最小生成树  给点的就用prim咯 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N = 10

ZOJ 1586 QS Network(kruskal)(基础)

Sunny Cup 2003 - Preliminary Round April 20th, 12:00 - 17:00 Problem E: QS Network In the planet w-503 of galaxy cgb, there is a kind of intelligent creature named QS. QScommunicate with each other via networks. If two QS want to get connected, they

ZOJ 1586 QS Network prim优化模板

链接: 1586 题意: 有一个N X N的网络,每两个点都有边相连,边的权值用邻接矩阵输入,每个点也有一个权值,当它们之间的那条边被选取时,需要加上两个点的权值.求这个网络的最小生成树. 直接套用prim算法的模板 其中用到一个节约内存的优化 将lowdistance 和visit 两个数组 结合起来 如果访问过lowdistance改成-1即可 另外该题中边的权值应为边本身的权值加上两端点的权值. #include<iostream> #include<cstdio> #inc

(最小生成树)QS Network -- ZOJ --1586

链接: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=1586 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=82831#problem/E 代码: #include <cstdio> #include <cstring> #include <cmath> #include <iostream> #include <

zoj 1586 QS Network

最小生成树,刚刚学了Prim算法. 对每条边变的权值进行预处理,c[i][j] = c[i][j] + p[i] + p[j] 其中c[i][j]为输入的权值,p[i],p[j]为连接这两个节点所需的费用. #include<stdio.h> #include<string.h> #include<math.h> #include<algorithm> using namespace std; const int maxn = 1010; int c[max

E - QS Network - zoj 1586(简单)

题意:在一个叫做QS的星系,他们使用一些特殊的通讯方式,两个人之间通讯需要使用一个网络适配器,但是一个网络适配器只能跟一个人联系,所有它连接几个人就需要及格适配器,而且每个人都有一些不同的偏好,喜欢的适配器的牌子也是不同的,现在让你求出来让QS人之间相互通讯最少需要多少代价? 输入第一行是测试数据组数,下面是一个N,代表N个人,下一样有N个数表示每个人喜欢的适配器的价格,接着一个矩阵,表示两点间通讯(电缆??)的价格. 分析:只要在每条边的权值上加上两个适配器的价格就可以了. *********