2014华为上机题

//2．求两个长长整型的数据的和并输出，例如输入1233333333333333。。。 3111111111111111111111111.。。。，则输出。。。。#include<stdio.h>
#include <iostream>
#include <string>

using namespace std;

int main()

{
    string num1, num2;//用于保存两个长整数
   cin >> num1 >> num2;
   cout << "num1="<< num1<<",num2="<<num2<<endl;
   int len1,len2,len;
   len1 = num1.length();
   len2 = num2.length();
   len = (len1>=len2)?len1:len2 ;
   int l = len;

    int sum_int[len]={0};//用数组保存每位数相加之和
    string sum(len+1,‘0‘);

    //cout << "sum.size=" <<  sizeof(sum_int)/sizeof(int) << "sum[0]="<< sum_int[0]<<endl;//tes
    //cout << "sum.size=" <<  sum.size() << "sum[0]="<< sum[0]<<endl;//test

    for(len1--,len2--;len1>=0&&len2>=0;len1--,len2--)
    {
        sum_int[len]=(num1[len1]-‘0‘) +(num2[len2]-‘0‘);
        cout << len << "," <<sum_int[len]<<endl;
        len--;
    }
    while(len1>=0)
    {
        sum_int[len] = num1[len1]-‘0‘;
        len--;
        len1--;
    }
     while(len2>=0)
    {
        sum_int[len] = num2[len2]-‘0‘;
        len--;
        len2--;
    }

    for(int j=l;j>=0;j--)
    {

        if(sum_int[j]>9)
        {
            sum_int[j-1]+=1;
            sum_int[j]=sum_int[j]%10;
        }
        //cout << sum_int[j]<<endl;
        sum[j] = sum_int[j]+‘0‘;
    }

    //跳过开始的0
    int k = 0;
    while(sum[k]==‘0‘)
        k++;
    sum = sum.substr(k,l+1);
    cout << sum << endl;

}

解法二：//用vector保存每位之和