1.百分号
95\%
2.下标
b_{ij}
3.表格（excel2latex）
- 符号说明
\begin{table}[H]
\centering
\begin{tabular}{m{100pt}<{\centering} m{100pt}<{\centering} m{200pt}<{\centering}}
\toprule
序列 & 符号& 符号说明\\midrule
1 & $t_{ij}$ & 第i个会员第j种DVD的态度\ 2 & $s_j$ & 愿意观看第j张的DVD的会员数 \ 3 & $p_j$ & 会员愿意观看第j种DVD的概率 \ 4 & $x_{ij}$ & 第i个会员是否被分配到第j张DVD \ 5 & $a_{ij}$ & 第i个会员对第j张DVD的满意度 \ 6 & $k_{i}$ & 第i个会员有没有被分配到DVD \ 7 & $c_j$ & 第j种DVD购买的数量 \ 8 & $b_{ij}$ & 第i个会员是否返还第j张DVD \ 9 & $w_j$ & 两阶段共需要购买的j种DVD数量 \ 10 & $z_{ij}$ & 第二阶段针第i个会员需求的第j种DVD \\bottomrule
\end{tabular}
\end{table}
- 一般表格【有表头】
\begin{table}[H]
\caption{会员对5种DVD的愿意观看概率}
\centering
\begin{tabular}{|c|c|c|c|c|c|}
\hline
$\mbox{DVD名称}$ & $\mbox{DVD1}$ & $\mbox{DVD2}$ & $\mbox{DVD3}$ & $\mbox{DVD4}$ & $\mbox{DVD5}$\ \hline
$\mbox{第j张愿意观看概率}$ & $0.2$ & 0.1 & $0.05$ & $0.025$ & $0.01$ \ \hline
\end{tabular}
\end{table}
- 改变字体大小
-
\tiny
- 双栏
\begin{table}[H]
\centering
\caption{前30个会员分配情况}
\begin{tabular}{r|rrr||r|rrr}
\toprule
会员编号 &DVD1&DVD2&DVD3& 会员编号&DVD1&DVD2&DVD3 \ \midrule
C001 & D008 & D041 & D098 & C016 & D010 & D084 & D097 \ C002 & D006 & D044 & D062 & C017 & D047 & D051 & D067 \ C003 & D032 & D050 & D080 & C018 & D041 & D060 & D078 \ C004 & D007 & D018 & D041 & C019 & D066 & D084 & D086 \ C005 & D011 & D066 & D068 & C020 & D045 & D061 & D089 \ C006 & D019 & D053 & D066 & C021 & D045 & D050 & D053 \ C007 & D026 & D066 & D081 & C022 & D038 & D055 & D057 \ C008 & D031 & D035 & D071 & C023 & D029 & D081 & D095 \ C009 & D053 & D078 & D100 & C024 & D037 & D041 & D076 \ C010 & D041 & D055 & D085 & C025 & D009 & D069 & D094 \ C011 & D059 & D063 & D066 & C026 & D022 & D068 & D095 \ C012 & D002 & D031 & D041 & C027 & D050 & D058 & D078 \ C013 & D021 & D078 & D096 & C028 & D008 & D034 & D082 \ C014 & D023 & D052 & D089 & C029 & D026 & D030 & D055 \ C015 & D013 & D052 & D085 & C030 & D037 & D062 & D098 \ \bottomrule
\end{tabular}%
\label{tab:addlabel}%
\end{table}%
4.等式
\begin{equation}
E=0.6*2+0.44*1=1.6
\end{equation}
\begin{equation*}
t_{ij}=
\begin{cases}
1,&\text{第i个会员愿意观看第j种DVD}\ 0,&\text{第i个会员不愿意观看第j种DVD}\ \end{cases}
\end{equation*}
- 求和
$$s_j=\sum_{i=1}^{100000}t_{ij},j=1,2,\ldots,5$$
- 极限
\begin{equation}
\lim_{n \to \infty}P(\frac{\eta_{x}-np}{\sqrt{np(1-p)}}\leq x)=\int _{-\infty}^{x}\frac{1}{\sqrt{2\pi}}e^{-\frac{t^2}{2}} dt
=\Phi (x)
\end{equation}
5.另起一段，另起一页
\par \newpage
6.字体加粗
\textbf{(2)三个月内95\%}
7.矩阵
$$X=\begin{pmatrix}
x_{1,1}&x_{1,2}&\ldots&x_{1,100}\x_{2,1}&x_{2,2}&\ldots&x_{2,100}\\vdots &\vdots & &\vdots\x_{1000,1}&x_{1000,2}&\ldots&x_{1000,100}\\end{pmatrix}$$
- 相乘
$$ \left(\begin{array}{c}
X_1 \X_2 \\dots \X_p
\end{array}\right)
=
\left(\begin{array}{cccc}
a_{11} & a_{12} & \dots &a_{1m} \a_{21} & a_{22} & \dots &a_{2m} \\dots & \dots & \dots &\dots \a_{p1} & a_{p2} & \dots &a_{pm} \\end{array}\right)
\left(\begin{array}{c}
F_1 \F_2 \\dots \F_m
\end{array}\right)
\left(\begin{array}{c}
\varepsilon_1 \\varepsilon_2 \\dots \\varepsilon_p
\end{array}\right)
$$
8.空格
\quad
9.线性规划
\begin{center}
$$max\sum\limits_{i=1}^{1000}\sum\limits_{j=1}^{100} = x_{ij}a_{ij} $$
\begin{equation*}
s.t.
\begin{cases}
\sum\limits_{j=1}^{100}x_{ij} = 3k_{i}\\sum\limits_{i=1}^{1000}x_{ij} \leq num_j,j = 1,2,\ldots,100 \x_{ij},k_{ij} = 0 \text{或} 1; \i = 1,2,\ldots,1000; \j = 1,2,\ldots,100 \\end{cases}
\end{equation*}
\end{center}
10.加帽子
\widehat{D_t}
11.参考文献
\bibitem{1}
12.附录
\zihao{5}\songti\thesection {附录1 \quad 第二题lingo实现代码}
\begin{verbatim}
\end{verbatim}
时间： 2024-10-11 20:53:32