Given a 2D binary matrix filled with 0‘s and 1‘s, find the largest square containing all 1‘s and return its area.
For example, given the following matrix:
1 0 1 0 0 1 0 1 1 1 1 1 1 1 1 1 0 0 1 0
Return 4.
Credits:
Special thanks to @Freezen for adding this problem and creating all test cases.
思路借鉴:dynamic programing. 以当前点(x,y) = ‘1‘ 为右下角的最大正方形的边长f(x,y) = min( f(x-1,y), f(x,y-1), f(x-1,y-1)) + 1.
代码如下:
public class Solution { public int maximalSquare(char[][] matrix) { if(matrix==null || matrix.length==0 || matrix[0].length==0) return 0; int n=matrix.length; int m=matrix[0].length; int [][]d=new int[n][m]; int max=0; for(int i=0;i<n;i++){ if(matrix[i][0]==‘1‘){ d[i][0]=1; max=1; } } for(int j=0;j<m;j++){ if(matrix[0][j]==‘1‘){ d[0][j]=1; max=1; } } for(int i=1;i<n;i++){ for(int j=1;j<m;j++){ if(matrix[i][j]==‘0‘) d[i][j]=0; else{ d[i][j]=Math.min(Math.min(d[i-1][j],d[i][j-1]),d[i-1][j-1])+1; max=Math.max(max,d[i][j]); } } } return max*max; } }
运行结果:
时间: 2024-10-15 12:37:28