excel有针对偏度的计算函数 skew(), 但是不清楚怎么使用excel进行遍历, 数据量很大。
尝试使用python进行解决。
第一次学习python,没想到了在克服安装各种包的难过之后,居然成功实现了。
python3.3:
#this is a test case # -*- coding: gbk -*- print("hello python!中文") #env config import xlrd import os import xlwt3 import numpy import pandas as pd #from pandas import Series,DataFrame #import pandas data = xlrd.open_workbook("E:\\data.xlsx") table = data.sheets()[0] #this need to be verify more #print ("check") print (table.nrows) print (table.name) print ("############################") #total line num line_num=table.nrows cell_sectionA=table.cell(1,0).value cell_sectionB=table.cell(1,1).value #print (cell_sectionA) #print (cell_sectionB) start_value=cell_sectionA #we need to recode the start value ,but not the end. sectionB_each_time_start=0 #sectionB_each_time_end=i is ok. for i in range(1,line_num): if start_value != table.cell(i,0).value: cacu_num=i-sectionB_each_time_start; #print (cacu_num) #print ("********************************") data={} for j in range(0,(cacu_num-1)): data[j]= table.cell((sectionB_each_time_start+j+1),1).value #print (data[j]) df = pd.Series(data) #print("skew\t") #print("skew: %d %f" %(table.cell(sectionB_each_time_start+1,0).value,df.skew())) print("%d"%table.cell(sectionB_each_time_start+1,0).value) #print("%f" %df.skew()) #after caculate ,update the variable. sectionB_each_time_start=i-1 start_value=table.cell(i,0).value #file=xlwt3.Workbook() #table_for_wt=file.add_sheet("test1"); #table_for_wt.write(0,0,cell_b) #table_for_wt.write(1,1,cell_b) #file.save(‘E:\\wtest.xls‘)
时间: 2024-11-10 14:09:30