HDU 3065 AC自动机

题意：

给多个模式串一个母串，求个模式串在母串中出现的次数。

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <queue>
#include <stack>
#include <cstdio>
#include <vector>
#include <string>
#include <cctype>
#include <complex>
#include <cassert>
#include <utility>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;
typedef pair<int,int> PII;
typedef long long ll;
#define lson l,m,rt<<1
#define pi acos(-1.0)
#define rson m+1,r,rt<<11
#define All 1,N,1
#define read freopen("in.txt", "r", stdin)
#define N 50010
const ll  INFll = 0x3f3f3f3f3f3f3f3fLL;
const int INF= 0x7ffffff;
const int mod =  1000000007;
char str[1010][55];
int n;
struct Trie{
    int ch[N][26],val[N],f[N],num,hao[1010];
    void init(){
        num=1;
        memset(ch,0,sizeof(ch));
        memset(val,0,sizeof(val));
        memset(f,0,sizeof(f));
        memset(hao,0,sizeof(hao));
    }
    void build(char *s,int index){
        int u=0,len=strlen(s);
        for(int i=0;i<len;++i)
        {
            int v=s[i]-‘A‘;
            if(!ch[u][v]){
                memset(ch[num],0,sizeof(ch[num]));
                ch[u][v]=num++;
            }
            u=ch[u][v];
        }
        val[u]=index;
    }
    void getfail(){
        queue<int>q;
        for(int i=0;i<26;++i)
            if(ch[0][i])
            q.push(ch[0][i]);
        while(!q.empty()){
            int r=q.front();
            q.pop();
            for(int i=0;i<26;++i)
            {
                int u=ch[r][i];
                if(!u){ch[r][i] = ch[f[r]][i];continue;}
                q.push(u);
                int v=f[r];
                while(v&&!ch[v][i])v=f[v];
                f[u]=ch[v][i];
            }
        }
    }
    void find(char *T){
        int u=0,len=strlen(T);
        for(int i=0;i<len;++i){
                if(T[i]<‘A‘||T[i]>‘Z‘){
                    u=0;
                    continue;
                }
            int v=T[i]-‘A‘;
            while(u&&ch[u][v]==0)
                u=f[u];
            u=ch[u][v];
            int tmp=u;
            while(tmp&&val[tmp]){
                hao[val[tmp]]++;
                tmp=f[tmp];
            }
        }
        for(int i=1;i<=n;++i){
          if(hao[i])
            printf("%s: %d\n",str[i],hao[i]);
        }
    }
}ac;
int main()
{
    char T[2000100];
        while(~scanf("%d",&n)){
        ac.init();
        for(int i=1;i<=n;++i){
            scanf("%s",str[i]);
            ac.build(str[i],i);
        }
        ac.getfail();
        scanf("%s",T);
        ac.find(T);
    }
return 0;
}