a letter and a number描述
- we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
- 输入
- On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
- 输出
- for each case, you should the result of y+f(x) on a line
- 样例输入
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6 R 1 P 2 G 3 r 1 p 2 g 3
- 样例输出
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19 18 10 -17 -14 -4
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解题思路:
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本题涉及n组数据,而每组数据开头都是字符,scanf读取字符是会先读取换行,所以应当在读取每行数据之前,用getchar将回车吃掉,否知只能读取一半数据。
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程序代码:
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#include<stdio.h> int main() { int n,y,i; char x; scanf("%d",&n); while(n--) { getchar(); scanf("%c%d",&x,&y); if(x>='a'&&x<='z') printf("%d\n",'a'-x-1+y); else if(x>='A'&&x<='Z') printf("%d\n",x-'A'+1+y); } return 0; }
时间: 2024-10-10 14:09:33