First One
Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 410 Accepted Submission(s): 111
Problem Description
soda has an integer array a1,a2,…,an.
Let S(i,j) be
the sum of ai,ai+1,…,aj.
Now soda wants to know the value below:
∑i=1n∑j=in(?log2S(i,j)?+1)×(i+j)
Note: In this problem, you can consider log20 as
0.
Input
There are multiple test cases. The first line of input contains an integer T,
indicating the number of test cases. For each test case:
The first line contains an integer n (1≤n≤105),
the number of integers in the array.
The next line contains n integers a1,a2,…,an (0≤ai≤105).
Output
For each test case, output the value.
Sample Input
1 2 1 1
Sample Output
12
Source
2015 Multi-University Training Contest 6
#include <bits/stdc++.h> using namespace std; typedef long long ll; #define prt(k) cout<<#k" = "<<k<<" " const int N = 100233; int a[N]; int n; int main() { int re; read(re); while (re--) { read(n); ll ans = 0; for (ll i=1;i<=n;i++) { read(a[i]); ans += i * (n-i+1) + (n-i+1)*(n+i)/2; } for (int k=1;k<40;k++) { ll lim = 1LL<<k; ll s = 0; for (ll i=1, j=1; i<=n; i++) { while (j<=n && s<lim) s+=a[j++]; j--; if (s >= lim) { ans += i * ll(n - j + 1) + ll(n + j) * ll(n - j + 1)/2; j++; } else break; s -= a[i]; } } printf("%I64d\n", ans); } return 0; }
版权声明:本文为博主原创文章,未经博主允许不得转载。