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class Program
{
static
void Main(string[] args)
{
int
mark = 19;
int
tem = ToErJin(mark);
Console.WriteLine("转成二进制后："
+ tem); // 打印“转成二进制后：10011”
int
mark2 = 10011;
int
tem2 = ToShijin(mark2);
Console.WriteLine("转成十进制后："
+ tem2);// 打印“转成十进制后：19”
}
/// <summary>
/// 转换为二进制
/// </summary>
/// <param name="value"></param>
/// <returns></returns>
public
static int ToErJin(int
value)
{
int
temp = 0;
int
shang = 1;
int
yushu;
while
(shang != 0)
{
shang = (int)value / 2;
yushu = value % 2;
value = shang;
temp += yushu;
if
(shang != 0)
{
temp = temp * 10;
}
}
//最后将 temp 倒序
string
tempStr = temp.ToString();
int
tempLength = tempStr.Length;
string
resultStr = string.Empty;
for
(int
i = 0; i < tempLength; i++)
{
resultStr = tempStr[i] + resultStr;
}
return
int.Parse(resultStr);
}
/// <summary>
/// 转换为十进制（主要算法：个位数 * 2的零次方 + 十位数 * 2的一次方 + 百位数 * 2的二次方 + ...）
/// </summary>
/// <param name="value"></param>
/// <returns></returns>
public
static int ToShijin2(int
value)
{
int
temp = 0;
int
shang = value;
int
yushu;
int
mark = 0;
while
(shang != 0)
{
yushu = shang % 10;
shang = shang / 10;
temp += yushu * (int)Math.Pow(2, mark);
mark++;
}
return
temp;
}
/// <summary>
/// 二进制转十进制的另一种方法（主要算法：1110111 = 1 * 2~6 + 1 * 2~5 + 1 * 2~4 + 0 * 2~3 + 1 * 2~2 + 1 * 2~1 + 1 * 2~0）
/// </summary>
/// <param name="value"></param>
/// <returns></returns>
public
static int ToShijin(int
value)
{
string
strValue = value.ToString();
int
valueLength = strValue.Length;
int
result = 0;
for
(int
i = 0; i < valueLength; i++)
{
result += int.Parse(strValue[i].ToString()) * (int)Math.Pow(2, valueLength - 1 - i);
}
return
result;
}
}
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