需求:对登录进行验证,用户名cy 密码123456才能登录进去;
登录进去后,将用户存在session中;
其他链接要来访问(除了登录链接),首先验证是否登录,对这个进行拦截;
com.cy.model.User.java:
package com.cy.model; public class User { private String userName; private String password; public String getUserName() { return userName; } public void setUserName(String userName) { this.userName = userName; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } }
com.cy.action.UserAction.java:
package com.cy.action; import java.util.Map; import com.cy.model.User; import com.cy.service.UserService; import com.opensymphony.xwork2.ActionContext; import com.opensymphony.xwork2.ActionSupport; public class UserAction extends ActionSupport{ private static final long serialVersionUID = 1L; private User user; private UserService userService = new UserService(); private String error; public String getError() { return error; } public void setError(String error) { this.error = error; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } @Override public String execute() throws Exception { if(userService.login(user)){ ActionContext actionContext = ActionContext.getContext(); Map<String, Object> session = actionContext.getSession(); session.put("currentUser", user); return SUCCESS; }else{ this.error = "用户名或密码错误"; return ERROR; } } }
com.cy.action.GrilAction.java:
package com.cy.action; import com.opensymphony.xwork2.ActionSupport; public class GrilAction extends ActionSupport{ private static final long serialVersionUID = 1L; @Override public String execute() throws Exception { System.out.println("看美女"); return SUCCESS; } }
com.cy.interceptor.LoginInterceptor.java:
package com.cy.interceptor; import java.util.Map; import javax.servlet.http.HttpServletRequest; import org.apache.struts2.ServletActionContext; import com.opensymphony.xwork2.ActionContext; import com.opensymphony.xwork2.ActionInvocation; import com.opensymphony.xwork2.interceptor.Interceptor; public class LoginInterceptor implements Interceptor{ private static final long serialVersionUID = 1L; public void destroy() { System.out.println("LoginInterceptor销毁"); } public void init() { System.out.println("LoginInterceptor初始化"); } public String intercept(ActionInvocation invocation) throws Exception { System.out.println("在Action执行之前"); ActionContext actionContext = invocation.getInvocationContext(); Map<String, Object> session = actionContext.getSession(); Object currentUser = session.get("currentUser"); String result = null; if(currentUser != null){ result = invocation.invoke(); }else{ HttpServletRequest request = (HttpServletRequest) invocation.getInvocationContext().get(ServletActionContext.HTTP_REQUEST); request.setAttribute("error", "请先登录!"); result = "error"; } System.out.println("在Action执行之后"); return result; } }
com.cy.service.UserService.java:
package com.cy.service; import com.cy.model.User; public class UserService { public boolean login(User user){ if("cy".equals(user.getUserName()) && "123456".equals(user.getPassword())){ return true; }else{ return false; } } }
struts.xml:
<?xml version="1.0" encoding="UTF-8" ?> <!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN" "http://struts.apache.org/dtds/struts-2.0.dtd"> <struts> <package name="manage" namespace="/" extends="struts-default"> <interceptors> <interceptor name="loginInterceptor" class="com.cy.interceptor.LoginInterceptor"></interceptor> <interceptor-stack name="myStack"> <interceptor-ref name="loginInterceptor"></interceptor-ref> <interceptor-ref name="defaultStack"></interceptor-ref> </interceptor-stack> </interceptors> <!-- package默认使用myStack 这个包下面的每个action默认使用myStack拦截器栈--> <default-interceptor-ref name="myStack"></default-interceptor-ref> <global-results> <result name="error">error.jsp</result> </global-results> <action name="gril" class="com.cy.action.GrilAction"> <result name="success">success.jsp</result> <!-- 定义了默认的拦截器栈,这里就注释掉 <interceptor-ref name="loginInterceptor"></interceptor-ref> <interceptor-ref name="defaultStack"></interceptor-ref> --> </action> <action name="user" class="com.cy.action.UserAction"> <result name="success">success.jsp</result> <!-- 因为登录的时候不需要进行登录验证,不需要使用loginInterceptor 因此这里就写defaultStack 写了defaultStack action就不会再使用其他的拦截器了。 --> <interceptor-ref name="defaultStack"></interceptor-ref> </action> </package> </struts>
success.jsp:
<body> 当前用户: ${currentUser.userName} </body>
error.jsp:
<body> 错误信息:${error} <a href="login.jsp">登录</a> </body>
login.jsp:
<body> <form action="user" method="post"> 用户名: <input type="text" name="user.userName"/><br> 密码: <input type="text" name="user.password"/><br> <input type="submit" value="登录" /> </form> </body>
测试:
没有登录,直接访问gril链接:
进行登录,并且登录成功:
再次访问gril链接就ok了,console:
在Action执行之前
看美女
在Action执行之后
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时间: 2024-10-23 10:54:47