想查找某个值的临近值,mysql能做到么?比如有个数字是12345,数据库里面有12340和12350这两个值,那么这两个值需要找出来. select col,min(ABS(col-xxx)) num from tb group by col having num< 限制差异范围 (因为abs本身是大于等于0) order by num limit 10;
1 引言 当更新字段缺少where语句时,mysql会提示一下错误代码: Error Code: 1175. You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column To disable safe mode, toggle the option in Preferences -> SQL Queries and reconnect. 0.000 se
题:想要查询出来所有逗号分隔的值为1的结果. 经分析,考虑前.中.后三种带1的情况以及只有一个1的情况即可. 查询sql: select * from user a where a.`password` like '1,%' or a.`password` like '%,1,%' or a.`password` like '%,1' or a.`password` = '1'; 原文地址:https://www.cnblogs.com/super-chao/p/9835382.html