九宫格、函数入门、判断某天为某年的第几天

九宫格

#!/usr/bin/env python
#!--coding:utf-8 --
#!shenjie :2018/1/28 22:58
#[email protected] :shenjie
#[email protected]: 2.py
#!/usr/bin/env python
#-- coding:utf-8 --

class NinePaper(object):
def init(self):
self.numbers = list()
for i in range(1, 10):
self.numbers.append(i)
print("numbers = {0}".format(self.numbers))
def run(self):
lines = [(x,y,z) for x in self.numbers for y in self.numbers if x!=y for z in self.numbers if x!=z and y!=z and x+y+z == 15]
for line1 in lines:
for line2 in lines:
if set(line1) & set(line2):
continue
for line3 in lines:
if set(line1) & set(line2) & set(line3):
continue
if line1[0] + line2[0] + line3[0] != 15:
continue
if line1[1] + line2[1] + line3[1] != 15:
continue
if line1[2] + line2[2] + line3[2] != 15:
continue
if line1[0] + line2[1] + line3[2] != 15:
continue
if line1[2] + line2[1] + line3[0] != 15:
continue
print(‘‘‘

        |_{0}_|_{1}_|_{2}_|
        |_{3}_|_{4}_|_{5}_|
        |_{6}_|_{7}_|_{8}_|
        ‘‘‘.format(line1[0], line1[1], line1[2], line2[0], line2[1], line2[2], line3[0], line3[1], line3[2],))

def main():
ninePaper = NinePaper()
ninePaper.run()

if name == ‘main‘:
main()

函数入门

判断某天为某年的第几天：
分析：以3月5日为例，应该先把前两个月的加起来，然后再加上5天即本年的第几天，特殊情况，闰年且输入月份大于3时需考虑多加一天

#!/usr/bin/env python

year = int(raw_input(‘year:\n‘))
month = int(raw_input(‘month:\n‘))
day = int(raw_input(‘day:\n‘))

months = (0,31,59,90,120,151,181,212,243,273,304,334)
if 0 <= month <= 12:
    sum = months[month - 1]
else:
    print ‘data error‘
sum += day
leap = 0
if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)):
    leap = 1
if (leap == 1) and (month > 2):
    sum += 1
print ‘it is the %dth day.‘ % sum

原文地址：http://blog.51cto.com/jacksoner/2066211