建立一个test表单
<form action="chuli.php" method="post"> <div>用户名:<input type="text" name="uid" /></div> <div>密码:<input type="password" name="pwd" /></div> <div><input type="submit" value="登录" /></div> </form> chuli.php <?php $_post["uid"]; $_post["pwd"]; //造连接对象 $db = new MySQLi("localhost","root","123","mydb"); //写SQL语句 $sql = "select password from login shere uid=‘{$uid}‘"; //执行SQL语句 $resulat = $db->query($sql); $n = $result->fetch_row(); //判断if($uid!="" && $pwd !=‘‘){ if($n[0]==$psd) { header(location:main.php); } else { echo"用户名或密码错误"; }}else{ echo"用户名或密码不能为空";} /*写SQL语句,不安全的登录方式
//注入攻击 $sql = "select count(*) from login where useename=‘{$uid}‘ and passwoed= ‘{$pwd}‘"; //执行SQL语句 $result = $db->query($sql); $n = $result->fetch_row(); if($n[0]>0) { header("location:main.php"); } else { echo"用户名或密码错误"; }*/
注入攻击,此种代码的写法登录不安全
时间: 2024-12-15 23:31:44