Linked List Cycle
Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
做完Linked List Cycle II在做这题简直就是阉割版。。
fast每次前进两步,slow每次前进一步,如果相遇则为true,否则false
class Solution
{
public:
bool hasCycle(ListNode *head)
{
if(head == NULL)
return false;
ListNode* fast = head;
ListNode* slow = head;
do
{
if(fast->next && slow->next)
{
fast = fast->next;
slow = slow->next;
}
else
return false;if(fast->next)
fast = fast->next;
else
return false;
}while(fast != slow);return true;
}
};
【LeetCode】Linked List Cycle,布布扣,bubuko.com
时间: 2024-12-09 23:19:49