[leetcode]301. Remove Invalid Parentheses 去除无效括号

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results.

Note: The input string may contain letters other than the parentheses ( and ).

Example 1:

Input: "()())()"
Output: ["()()()", "(())()"]
Example 2:

Input: "(a)())()"
Output: ["(a)()()", "(a())()"]
Example 3:

Input: ")("
Output: [""]

原文地址：https://www.cnblogs.com/liuliu5151/p/9808254.html

时间： 2024-10-25 07:57:28

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题目如下: 解题思路:还是这点经验,对于需要输出整个结果集的题目,对性能要求都不会太高.括号问题的解法也很简单,从头开始遍历输入字符串并对左右括号进行计数,其中出现右括号数量大于左括号数量的情况,表示这个区间是不合法的,需要删掉一个右括号:遍历完成后,如果左括号数量大于右括号的数量,那么需要删除左括号,直至两者相等. 代码如下: class Solution(object): def removeInvalidParentheses(self, s): """ :type s