Hat‘s Fibonacci
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 7857 Accepted Submission(s): 2553
Problem Description
A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.
F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)
Your task is to take a number as input, and print that Fibonacci number.
Input
Each line will contain an integers. Process to end of file.
Output
For each case, output the result in a line.
Sample Input
100
Sample Output
4203968145672990846840663646 Note: No generated Fibonacci number in excess of 2005 digits will be in the test data, ie. F(20) = 66526 has 5 digits.#include<iostream> #include<cstring> #include<cstdio> using namespace std; //No generated Fibonacci number in excess of 2005 digits int a[10000][260]; //260*8=2080 > 2005 不能过大 ,容易超内存 int main() { int i,j,n; memset(a,0,sizeof(a)); a[1][0]=a[2][0]=a[3][0]=a[4][0]=1; for(i=5;i<10000;i++) { for(j=0;j<260;j++) a[i][j]=a[i-1][j]+a[i-2][j]+a[i-3][j]+a[i-4][j]; for(j=0;j<260;j++){ if(a[i][j]>=100000000) { int temp=a[i][j]/100000000; a[i][j]=a[i][j]%100000000; a[i][j+1]+=temp; } } } while(cin>>n){ for(i=259;i>0;i--) if(a[n][i]!=0) break; cout<<a[n][i]; //最后一个数不一定是刚好8位,要单独输出,否则数的前面会出现 0000 for(j=i-1;j>=0;j--) printf("%08d",a[n][j]); //printf("%8d",a[n][j]); 输出时会出现 空格 %08d则将空格补0 cout<<endl; } return 0; }
HDoj-1250-Hat's Fibonacci-大数
时间: 2024-11-09 10:16:19