leetCode题解之反转二叉树

1、题目描述

经典的反转二叉树,就是将二叉树中每个节点的左、右儿子交换。

2、题目分析

3、代码

 1 TreeNode* invertTree(TreeNode* root) {
 2
 3         if(root == NULL )
 4             return NULL;
 5
 6
 7         TreeNode* temp;
 8         temp = root->left;
 9         root->left = invertTree(root->right);
10         root->right = invertTree(temp);
11
12         return root;
13
14     }

原文地址:https://www.cnblogs.com/wangxiaoyong/p/8686801.html

时间: 2024-10-06 19:11:20

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