G - Beautiful People
Time Limit: 10000/5000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others)
Special Judge
Problem Description
The most prestigious sports club in one city has exactly N members. Each of its members is strong and beautiful. More precisely, i-th member of this club (members being numbered by the time they entered the
club) has strength Si and beauty Bi. Since this is a very prestigious club, its members are very rich and therefore extraordinary people, so they often extremely hate each other. Strictly speaking, i-th member of the club Mr X hates j-th member of the club
Mr Y if Si <= Sj and Bi >= Bj or if Si >= Sj and Bi <= Bj (if both properties of Mr X are greater then corresponding properties of Mr Y, he doesn‘t even notice him, on the other hand, if both of his properties are less, he respects Mr Y very much).
To celebrate a new 2003 year, the administration of the club is planning to organize a party. However they are afraid that if two people who hate each other would simultaneouly attend the party, after a drink
or two they would start a fight. So no two people who hate each other should be invited. On the other hand, to keep the club prestige at the apropriate level, administration wants to invite as many people as possible.
Being the only one among administration who is not afraid of touching a computer, you are to write a program which would find out whom to invite to the party.
Input
The first line of the input file contains integer N — the number of members of the club. (2 ≤ N ≤ 100 000). Next N lines contain two numbers each — Si and
Bi respectively (1 ≤ Si, Bi ≤
109).
Output
On the first line of the output file print the maximum number of the people that can be invited to the party. On the second line output N integers — numbers of members to be invited in arbitrary order. If several solutions exist, output any one.
Sample Input
4 1 1 1 2 2 1 2 2
Sample Output
2 1 4
题意：给了n个数对x,y，要求找出最长的数对，使得每一维都严格递增
思路：最长上升子序列，只不过是2维的，可以先按x排序以后按顺序用线段树维护就好了
具体维护的是，以每个y点结尾的最大长度
注意更新的时候先将同一个x下的y全部查询完了以后记录，再统一更新，因为x相等的点是不可以够成上升序列的