def q32(n, len): if n < 0: return 0 elif n <= 1: return n total = 0 while n > 0: if n >= 1 and n < 10: total += 1 return total p1 = n % (10**(len - 1)) h = n / (10**(len - 1)) p2 = p1 + 1 n = p1 if h > 1: total += 10**(len - 1) else: total += p2 total += 10 **(len -2) * h * (len - 1) return total
【剑指offer】Q32:从1到n整数1出现的次数(python)
时间: 2024-10-07 04:45:15