函数指针的一个的demo

#include <stdio.h>

typedef void (*fun_cb)(int a, int b);

static fun_cb exe_fun_cb;

void fun_cb_input(int, int);
void setUp_cb(fun_cb);

void main()
{
        setUp_cb(fun_cb_input);
}

void setUp_cb(fun_cb fun_cb_param)
{
        printf("\n ready to use callback \n");
        exe_fun_cb = fun_cb_param;
        if(exe_fun_cb)
        {
                exe_fun_cb(0, 0);
        }
}

void fun_cb_input(int param1, int param2)
{
        printf("\n this is a callback function!\n");
}

运行结果：