Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.
1 /** 2 * Definition for singly-linked list. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int x) { 7 * val = x; 8 * next = null; 9 * } 10 * } 11 */ 12 public class Solution { 13 public ListNode mergeKLists(List<ListNode> lists) { 14 if (lists == null || lists.size() == 0) { 15 return null; 16 } 17 Comparator<ListNode> compare=new Comparator<ListNode>() { 18 @Override 19 public int compare(ListNode o1, ListNode o2) { 20 return o1.val - o2.val; 21 } 22 }; 23 24 PriorityQueue<ListNode> queue = new PriorityQueue<ListNode>(lists.size(), compare); 25 for (ListNode node : lists) { 26 if (node != null) { 27 queue.add(node); 28 } 29 } 30 ListNode ret = new ListNode(0); 31 ListNode temp = ret; 32 while (!queue.isEmpty()) { 33 temp.next=queue.poll(); 34 temp=temp.next; 35 if (temp.next != null) { 36 queue.add(temp.next); 37 } 38 } 39 return ret.next; 40 } 41 42 }
时间: 2024-11-10 14:21:30