Python Tuple元组的操作说明

Tuple的特性在于，它的元素是不可变的(immutable)，一旦设定，就不能使用索引去修改。

>>> t1=1,2,3,4,5 #给Tuple赋值
>>> t1[0] #按照索引读取Tuple元素
1
>>> u1=t1,(2,3,4,5,6)#tuple可以嵌套
>>> u1
((1, 2, 3, 4, 5), (2, 3, 4, 5, 6))
>>> u1[1]
(2, 3, 4, 5, 6)
>>> u1[-1]
(2, 3, 4, 5, 6)
>>> u1=t1,(2,3,4,5,6),3
>>> u1
((1, 2, 3, 4, 5), (2, 3, 4, 5, 6), 3)
>>> list1=[‘we‘,‘the‘,‘north‘]
>>> list1
[‘we‘, ‘the‘, ‘north‘]
>>> u1=t1,list1
>>> u1
((1, 2, 3, 4, 5), [‘we‘, ‘the‘, ‘north‘])
>>> list1[-1]=‘toronto‘#元组内的元素是可变的，所以可以修改内部元素来更新元组
>>> u1
((1, 2, 3, 4, 5), [‘we‘, ‘the‘, ‘toronto‘])
>>> len(u1)
2
>>> myList = [1,2,3,4,5,6,7,8,9,10]
>>> myTuple = (1,2,3,4,5,6,7,8,9,10)
>>> myList=(2,)#初始化一个元素的时候，需要带comma
>>> myList
(2,)
>>> myList[0]
2
>>> myList[1]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
IndexError: tuple index out of range
>>> len(myList)
1

原文地址：https://www.cnblogs.com/rhyswang/p/8148410.html