PAT 1099. Build A Binary Search Tree (30)

1099. Build A Binary Search Tree (30)

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

  • The left subtree of a node contains only nodes with keys less than the node‘s key.
  • The right subtree of a node contains only nodes with keys greater than or equal to the node‘s key.
  • Both the left and right subtrees must also be binary search trees.

    Given the structure of a binary tree and a sequence of distinct integer keys, there is only one way to fill these keys into the tree so that the resulting tree satisfies the definition of a BST. You are supposed to output the level order traversal sequence of that tree. The sample is illustrated by Figure 1 and 2.

    Input Specification:

    Each input file contains one test case. For each case, the first line gives a positive integer N (<=100) which is the total number of nodes in the tree. The next N lines each contains the left and the right children of a node in the format "left_index right_index", provided that the nodes are numbered from 0 to N-1, and 0 is always the root. If one child is missing, then -1 will represent the NULL child pointer. Finally N distinct integer keys are given in the last line.

    Output Specification:

    For each test case, print in one line the level order traversal sequence of that tree. All the numbers must be separated by a space, with no extra space at the end of the line.

    Sample Input:

    9
    1 6
    2 3
    -1 -1
    -1 4
    5 -1
    -1 -1
    7 -1
    -1 8
    -1 -1
    73 45 11 58 82 25 67 38 42
    

    Sample Output:

    58 25 82 11 38 67 45 73 42

此题只需要知道BST的前序遍历为递增的序列就可以轻松的设置各个节点的值了

 1 #include <iostream>
 2 #include <vector>
 3 #include <algorithm>
 4 #include <queue>
 5
 6 using namespace std;
 7
 8 struct Node
 9 {
10     int value;
11     int left = -1;
12     int right = -1;
13 };
14
15 Node tree[100];
16 int num[100];
17 int cnt = 0;
18
19 void PreTraversal(int root)    //use preorder traversal to set the value
20 {
21     if (root == -1)
22         return;
23     PreTraversal(tree[root].left);
24     tree[root].value = num[cnt++];
25     PreTraversal(tree[root].right);
26 }
27
28 void levelTraversal(int root)
29 {
30     queue<int> que;
31     que.push(root);
32     while (!que.empty())
33     {
34         int index = que.front();
35         que.pop();
36         if (index != root)
37             cout << " ";
38         cout << tree[index].value;
39         if (tree[index].left != -1)
40             que.push(tree[index].left);
41         if (tree[index].right != -1)
42             que.push(tree[index].right);
43     }
44 }
45
46 int main()
47 {
48     int n;
49     cin >> n;
50     for (int i = 0; i < n; i++)
51         cin >> tree[i].left >> tree[i].right;
52     for (int i = 0; i < n; i++)
53         cin >> num[i];
54     sort(num, num + n);
55
56     PreTraversal(0);
57     levelTraversal(0);
58 }
时间: 2024-10-03 19:24:51

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