题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=4716
Problem Description
In this problem we talk about the study of Computer Graphics. Of course, this is very, very hard.
We have designed a new mobile phone, your task is to write a interface to display battery powers.
Here we use ‘.‘ as empty grids.
When the battery is empty, the interface will look like this:
*------------* |............| |............| |............| |............| |............| |............| |............| |............| |............| |............| *------------*
When the battery is 60% full, the interface will look like this:
*------------* |............| |............| |............| |............| |------------| |------------| |------------| |------------| |------------| |------------| *------------*
Each line there are 14 characters.
Given the battery power the mobile phone left, say x%, your task is to output the corresponding interface. Here x will always be a multiple of 10, and never exceeds 100.
Input
The first line has a number T (T < 10) , indicating the number of test cases.
For each test case there is a single line with a number x. (0 < x < 100, x is a multiple of 10)
Output
For test case X, output "Case #X:" at the first line. Then output the corresponding interface.
See sample output for more details.
Sample Input
2 0 60
Sample Output
Case #1: *------------* |............| |............| |............| |............| |............| |............| |............| |............| |............| |............| *------------* Case #2: *------------* |............| |............| |............| |............| |------------| |------------| |------------| |------------| |------------| |------------| *------------*
Source
2013 ACM/ICPC Asia Regional Online —— Warmup2
代码如下：
#include <stdio.h>
#include <string.h>
int main()
{
int t,i,j,n,cas=1;
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
char mp[20][20]= {"*------------*",
"|............|",
"|............|",
"|............|",
"|............|",
"|............|",
"|............|",
"|............|",
"|............|",
"|............|",
"|............|",
"*------------*"
};
n/=10;
for(i=1; i<=n; i++)
{
for(j=1; j<=12; j++)
mp[11-i][j]='-';
}
printf("Case #%d:\n",cas++);
for(i=0; i<12; i++)
{
for(j=0; j<14; j++)
{
printf("%c",mp[i][j]);
}
printf("\n");
}
}
return 0;
}