原题地址:https://oj.leetcode.com/problems/subsets-ii/
题意:
Given a collection of integers that might contain
duplicates, S, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For
example,
If S = [1,2,2]
,
a solution is:
[
[2],
[1],
[1,2,2],
[2,2],
[1,2],
[]
]
解题思路:和上一道题一样,求一个集合的所有子集。和上一道题不一样的一点是集合可能有重复元素。这道题同样使用dfs来解题,只是需要在dfs函数里加一个剪枝的条件,排除掉同样的子集。
代码:
class Solution:
# @param num, a list of integer
# @return a list of lists of integer
def subsetsWithDup(self, S):
def dfs(depth, start, valuelist):
if valuelist not in res: res.append(valuelist)
if depth == len(S): return
for i in range(start, len(S)):
dfs(depth+1, i+1, valuelist+[S[i]])
S.sort()
res = []
dfs(0, 0, [])
return res
[leetcode]Subsets II @ Python,布布扣,bubuko.com
时间: 2024-10-11 12:03:08