hdu 1711 Number Sequence(KMP)

# include <stdio.h>
# include <string.h>
# include <algorithm>
using namespace std;
int n,m,next[10010],a[1000010],b[10010];
void Getnext()
{
    int i=0,j=-1;
    next[0]=-1;
    while(i<m)
    {
        if(j==-1||b[i]==b[j])
            i++,j++,next[i]=j;
        else
            j=next[j];
    }
}
int KMP()
{
    int i=0,j=0;
    while(i<n&&j<m)
    {
        if(j==-1||a[i]==b[j])
            i++,j++;
        else
            j=next[j];
    }
    if(j==m)
        return i-j+1;
    return 0;
}
int  main()
{
    int t,i;
    while(~scanf("%d",&t))
    {
        while(t--)
        {
            scanf("%d%d",&n,&m);
            for(i=0;i<n;i++)
                scanf("%d",&a[i]);
            for(i=0;i<m;i++)
                scanf("%d",&b[i]);
            Getnext();
            int ans=KMP();
            if(ans)
                printf("%d\n",ans);
            else
                printf("-1\n");
        }
    }
    return 0;
}

hdu 1711 Number Sequence(KMP),布布扣,bubuko.com

时间: 2024-10-11 23:51:26

hdu 1711 Number Sequence(KMP)的相关文章

HDU 1711 Number Sequence KMP题解

KMP查找整数数列,不是查找字符串. 原理是一样的,不过把字符串转换为数列,其他基本上是一样的. #include <stdio.h> #include <string.h> const int MAX_N = 1000001; const int MAX_M = 10001; int strN[MAX_N], strM[MAX_M], next[MAX_M], N, M; void getNext() { memset(next, 0, sizeof(int) * M); for

HDU - 1711 Number Sequence KMP字符串匹配

HDU - 1711 Number Sequence Time Limit: 5000MS   Memory Limit: 32768KB   64bit IO Format: %I64d & %I64u Submit Status Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <=

HDU 1711 Number Sequence(KMP算法)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 15548    Accepted Submission(s): 6836 Problem Description Given two sequence

hdu 1711 Number Sequence KMP 基础题

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11691    Accepted Submission(s): 5336 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],

(KMP 1.1)hdu 1711 Number Sequence(KMP的简单应用——求pattern在text中第一次出现的位置)

题目: Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 12902    Accepted Submission(s): 5845 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1

HDU 1711 Number Sequence(KMP模板)

Problem Description: Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1]

hdu 1711 Number Sequence KMP模板题

题意:给你两个数组,求第二个数组在第一个数组中的位置,若不存在,则输出-1. #include <cstdio> #include <cmath> #include <iostream> #include <string.h> #include <algorithm> using namespace std; int d[10005]; int f[1000005]; int Next[20005]; void KMP(int s[],int l

KMP算法的定义及KMP练手题 HDU 1711 Number Sequence (我的模板代码)

题意:就是要你来找出b数组在a数组中最先匹配的位置,如果没有则输出-1 思路:直接KMP算法(算法具体思想这位牛写的不错http://blog.csdn.net/v_july_v/article/details/7041827) AC代码: #include<cstdio> #include<cstring> #include<stdlib.h> #include<iostream> using namespace std; #define maxn 100

HDU 1711 Number Sequence(字符串匹配)

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 10571    Accepted Submission(s): 4814 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],