我正在寻找一种方法来轻松地将python列表分成两半.
所以,如果我有一个数组:
A = [0,1,2,3,4,5]
我能得到:
B = [0,1,2]
C = [3,4,5]
最佳答案
A = [1,2,3,4,5,6]
B = A[:len(A)//2]
C = A[len(A)//2:]
如果你想要一个功能:
def split_list(a_list):
half = len(a_list)//2
return a_list[:half], a_list[half:]
A = [1,2,3,4,5,6]
B, C = split_list(A)
原文地址:https://www.cnblogs.com/shengs/p/12264192.html
时间: 2024-07-31 12:24:45