基准时间限制：1 秒 空间限制：131072 KB 分值: 0 难度：基础题
给出2个大整数A,B，计算A+B的结果。
Input
第1行：大数A 第2行：大数B (A,B的长度 <= 10000 需注意：A B有可能为负数）
Output
输出A + B
Input示例
68932147586 468711654886
Output示例
537643802472 c++代码
1 #include <iostream>
2 #include <cstring>
3 #include <bits/stdc++.h>
4 using namespace std;
5
6 string bigadd(string s,string ss){
7 string tt;
8 int slen = s.length();
9 int sslen = ss.length();
10 reverse(s.begin(),s.end());
11 reverse(ss.begin(),ss.end());
12 int index = 0;
13 for(int i=0;i<min(slen,sslen);i++){
14 int a = s[i]-‘0‘,b = ss[i]-‘0‘;
15 int at = a+b+index;
16 if(at>9){
17 tt+=at-10+‘0‘;
18 index = 1;
19 }else{
20 tt+=at+‘0‘;
21 index = 0;
22 }
23 }
24 for(int i=min(slen,sslen);i<max(slen,sslen);i++){
25 if(slen>i){
26 int a = s[i]-‘0‘;
27 int at = a+index;
28 if(at>9){
29 tt+=at-10+‘0‘;
30 index = 1;
31 }else{
32 tt+=at+‘0‘;
33 index = 0;
34 }
35 }else{
36 int b = ss[i]-‘0‘;
37 int at = b+index;
38 if(at>9){
39 tt+=at-10+‘0‘;
40 index = 1;
41 }else{
42 tt+=at+‘0‘;
43 index = 0;
44 }
45 }
46 }
47 if(index){
48 tt+=‘1‘;
49 }
50 reverse(tt.begin(),tt.end());
51 return tt;
52 }
53
54 string bigdel(string s,string ss){//s>=ss
55 string tt,st;
56 int slen = s.length();
57 int sslen = ss.length();
58 reverse(s.begin(),s.end());
59 reverse(ss.begin(),ss.end());
60 int index = 0;
61 for(int i=0;i<sslen;i++){
62 int a = s[i]-‘0‘;
63 int b = ss[i]-‘0‘;
64 int at = a-b-index;
65 if(at<0){
66 tt+=at+10+‘0‘;
67 index = 1;
68 }else{
69 tt+=at+‘0‘;
70 index = 0;
71 }
72 }
73 for(int i=sslen;i<slen;i++){
74 int b = s[i]-‘0‘;
75 int at = b - index;
76 if(at<0){
77 tt+=at+10+‘0‘;
78 index = 1;
79 }else{
80 tt+=at+‘0‘;
81 index = 0;
82 }
83 }
84 bool prime = true;
85 for(int i = slen-1;i>=0;i--){
86 if(tt[i]!=‘0‘){
87 prime = false;
88 }
89 if(!prime){
90 st+=tt[i];
91 }
92 }
93 if(st.length()==0)
94 st+=‘0‘;
95 return st;
96 }
97
98 int compare(string s,string ss){
99 int slen = s.length();
100 int sslen = ss.length();
101 if(slen==sslen){
102 for(int i=0;i<slen;i++){
103 if(s[i]==ss[i]){
104 continue;
105 }else{
106 return s[i]>ss[i];
107 }
108 }
109 }else{
110 return slen > sslen;
111 }
112 return 2;
113 }
114 string s,ss;
115 int main(){
116 while(cin>>s>>ss){
117 bool sflag=true, ssflag=true;
118 if(s[0]==‘-‘){
119 s.erase(0,1);
120 sflag = false;
121 }
122 if(ss[0]==‘-‘){
123 ss.erase(0,1);
124 ssflag = false;
125 }
126 if((sflag&&ssflag)||(!sflag&&!ssflag)){
127 string st = bigadd(s,ss);
128 if(sflag)
129 cout<<st<<endl;
130 else{
131 st=‘-‘+st;
132 cout<<st<<endl;
133 }
134 }else{
135 string st;
136 if(sflag){//s为正数
137 if(compare(s,ss)==0){
138 st = bigdel(ss,s);
139 st=‘-‘+st;
140 cout<<st<<endl;
141 }else if(compare(s,ss)==1){
142 st = bigdel(s,ss);
143 cout<<st<<endl;
144 }else{
145 cout<<"0"<<endl;
146 }
147 }else{//ss为正数
148 if(compare(s,ss)==0){
149 st = bigdel(ss,s);
150 cout<<st<<endl;
151 }else if(compare(s,ss)==1){
152 st = bigdel(s,ss);
153 st=‘-‘+st;
154 cout<<st<<endl;
155 }else{
156 cout<<"0"<<endl;
157 }
158 }
159 }
160 }
161 return 0;
162 }
JAVA：
1 import java.util.*;
2 import java.io.*;
3 import java.lang.String;
4 import java.math.BigDecimal;
5
6 public class p1036
7 {
8 public static void main(String[] args)
9 {
10 String s1,s2;
11 Scanner cin = new Scanner(System.in);
12 s1 = cin.next();
13 s2 = cin.next();
14 BigDecimal b1 = new BigDecimal(s1);
15 BigDecimal b2 = new BigDecimal(s2);
16 System.out.println(b1.add(b2));
17 cin.close();
18 }
19 }
原文地址：https://www.cnblogs.com/zllwxm123/p/8945225.html
时间： 2024-08-02 05:06:16