首先来看split的源码:
public String[] split(String regex, int limit) { /* fastpath if the regex is a (1)one-char String and this character is not one of the RegEx‘s meta characters ".$|()[{^?*+\\", or (2)two-char String and the first char is the backslash and the second is not the ascii digit or ascii letter. */ char ch = 0; if (((regex.value.length == 1 && ".$|()[{^?*+\\".indexOf(ch = regex.charAt(0)) == -1) || (regex.length() == 2 && regex.charAt(0) == ‘\\‘ && (((ch = regex.charAt(1))-‘0‘)|(‘9‘-ch)) < 0 && ((ch-‘a‘)|(‘z‘-ch)) < 0 && ((ch-‘A‘)|(‘Z‘-ch)) < 0)) && (ch < Character.MIN_HIGH_SURROGATE || ch > Character.MAX_LOW_SURROGATE)) { int off = 0; int next = 0; boolean limited = limit > 0; ArrayList<String> list = new ArrayList<>(); while ((next = indexOf(ch, off)) != -1) { if (!limited || list.size() < limit - 1) { list.add(substring(off, next)); off = next + 1; } else { // last one //assert (list.size() == limit - 1); list.add(substring(off, value.length)); off = value.length; break; } } // If no match was found, return this if (off == 0) return new String[]{this};
// Add remaining segment if (!limited || list.size() < limit) list.add(substring(off, value.length));
// Construct result int resultSize = list.size(); if (limit == 0) { while (resultSize > 0 && list.get(resultSize - 1).length() == 0) { resultSize--; } } String[] result = new String[resultSize]; return list.subList(0, resultSize).toArray(result); } //重点 return Pattern.compile(regex).split(this, limit);}
通过split方法的源码可以发现,在大部分情况下,split函数实际上是新建了一个Pattern对象,再去调用它的split函数,因此,如果我们一直调用String的split方法,就相当于在一直新建Pattern对象,会明显多占用内存,降低程序运行速度。此时可以对代码进行改进:
Pattern pattern = Pattern.complie("[(*&(*%^*%]");
for(String line : lines){
pattern.split(line);
}
String中其它一些会在内部生成Pattern对象的函数还包括:
matches
replaceFirst
replaceAll
原文地址:https://www.cnblogs.com/yuanfei1110111/p/10134289.html
时间: 2024-11-14 20:14:22