152. Maximum Product Subarray java solutions

Find the contiguous subarray within an array (containing at least one number) which has the largest product.

For example, given the array [2,3,-2,4],
the contiguous subarray [2,3] has the largest product = 6.

记录当前最大, 最小值. 因为遇到负数时, 与最小值的乘积可能成为最大值.

 1 public class Solution {
 2     public int maxProduct(int[] nums) {
 3         if(nums == null || nums.length < 1) return 0;
 4         int ans = nums[0];
 5         int max = nums[0], min = nums[0];
 6         for(int i = 1; i < nums.length; i++){
 7             int tmp1 = max*nums[i];
 8             int tmp2 = min*nums[i];
 9             max = Math.max(nums[i],Math.max(tmp1,tmp2));
10             min = Math.min(nums[i],Math.min(tmp1,tmp2));
11             ans = Math.max(max,ans);
12         }
13         return ans;
14     }
15 }
时间: 2024-12-12 19:48:30

152. Maximum Product Subarray java solutions的相关文章

leetcode 152. Maximum Product Subarray --------- java

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. 找出最大的相乘的数字,很简单,代码还可以优化的地方很多.但是速度还可以. publi

152. Maximum Product Subarray(js)

152. Maximum Product Subarray Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product

刷题152. Maximum Product Subarray

一.题目说明 题目152. Maximum Product Subarray,给一列整数,求最大连续子序列,其乘积最大.难度是Medium! 二.我的解答 这个题目,用双重循环就可以了. class Solution{ public: int maxProduct(vector<int>& nums){ if(nums.size()<=1) return nums[0]; product = INT_MIN; int len = nums.size(); for(int i=0;

【LeetCode】152. Maximum Product Subarray

题目: Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. 题解: 先暴力解,遍历所有组合,更新最大值.很显然得超时. Solution

LeetCode 152. Maximum Product Subarray (最大乘积子数组)

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. 题目标签:Array, Dynamic Programming 题目给了我们一个nu

Java for LeetCode 152 Maximum Product Subarray

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4], the contiguous subarray [2,3] has the largest product = 6. 解题思路: 计算连续的积最大,由于会有负数出现,因此需要用两个int表示包含num

(Java) LeetCode 152. Maximum Product Subarray —— 乘积最大子序列

Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6. Example 2: Input: [-2,0,-1]

[LeetCode] 152. Maximum Product Subarray 求最大子数组乘积

Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6. Example 2: Input: [-2,0,-1]

152. Maximum Product Subarray (Array; DP)

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. 思路:类似Maximum Subarray,不同的是 max(max_local*n